Question

我正在尝试将每行中的key = value对分组到一个按ID分组的行中。

表1. wp_posts
键：ID - post_title

表2. wp_postmeta
键：post_id，wpcf-owner，wpcf-tel，wpcf-mob，wpcf-email ......

使用此查询，我获取所有信息，但是对于每个键，我得到单独的行。我需要的是一个数组，其中all由wp_posts.ID

组成一行

SELECT wp_posts.ID, wp_posts.post_title, wp_postmeta.post_id, wp_postmeta.meta_key, wp_postmeta.meta_value
FROM wp_posts
JOIN wp_postmeta
ON wp_posts.ID = wp_postmeta.post_id
WHERE wp_posts.post_type = 'accommodation' AND wp_postmeta.meta_key LIKE 'wpcf%'
ORDER BY hic13_posts.post_title

结果是：

ID | post_title | key value  
------------------------------  
1  |  TITLE     |  wpcf-owner  
1  |  TITLE     |  wpcf-tel  
1  |  TITLE     |  wpcf-mob  
1  |  TITLE     |  wpcf-email  
2  |  TITLE     |  wpcf-owner  
2  |  TITLE     |  wpcf-tel  
2  |  TITLE     |  wpcf-mob  
2  |  TITLE     |  wpcf-email  
...

我需要的是：

ID | post_title | key value  | key value | key value | key value  
-----------------------------------------------------------------  
1  |  TITLE     | wpcf-owner | wpcf-tel  | wpcf-mob  | wpcf-email  
2  |  TITLE     | wpcf-owner | wpcf-tel  | wpcf-mob  | wpcf-email

如果我按ID添加命令，那么我只从第二个表中获得一个键...

SELECT wp_posts.ID, wp_posts.post_title, wp_postmeta.post_id, wp_postmeta.meta_key, wp_postmeta.meta_value
FROM wp_posts
JOIN wp_postmeta
ON wp_posts.ID = wp_postmeta.post_id
WHERE wp_posts.post_type = 'accommodation' AND wp_postmeta.meta_key LIKE 'wpcf%'    
GROUP BY hic13_posts.ID
ORDER BY hic13_posts.post_title

我只得到这个

ID | post_title | key value  
------------------------------  
1  |  TITLE     |  wpcf-owner  
2  |  TITLE     |  wpcf-tel

希望这一切都有道理:-)
谢谢！

Answer 1

此类转换是 pivot ，但MySQL没有pivot函数，因此您需要使用带有CASE表达式的聚合函数。：

SELECT p.ID, 
  p.post_title, 
  m.post_id, 
  max(case when m.meta_key = 'wpcf-owner' then m.meta_value end) as owner,
  max(case when m.meta_key = 'wpcf-tel' then m.meta_value end) as tel,
  max(case when m.meta_key = 'wpcf-mob' then m.meta_value end) as mob,
  max(case when m.meta_key = 'wpcf-email' then m.meta_value end) as email
FROM wp_posts p
JOIN wp_postmeta m
  ON p.ID = m.post_id
WHERE p.post_type = 'accommodation' AND m.meta_key LIKE 'wpcf%'    
GROUP BY p.ID, p.post_title, m.post_id
ORDER BY p.post_title

编辑，如果要转换的meta_key个项目数量未知，则可以使用预准备语句生成动态sql：

SET @sql = NULL;
SELECT
  GROUP_CONCAT(DISTINCT
    CONCAT(
      'max(CASE WHEN m.meta_key = ''',
      meta_key,
      ''' THEN m.meta_value else null END) AS `',
      meta_key, '`'
    )
  ) INTO @sql
FROM wp_postmeta;

SET @sql 
  = CONCAT('SELECT p.ID, 
              p.post_title, 
              m.post_id, ', @sql, ' 
            FROM wp_posts p
            JOIN wp_postmeta m
              ON p.ID = m.post_id
            WHERE p.post_type = ''accommodation'' 
               AND m.meta_key LIKE ''wpcf%''   
            GROUP BY p.ID, p.post_title, m.post_id
            ORDER BY p.post_title');

PREPARE stmt FROM @sql;
EXECUTE stmt;
DEALLOCATE PREPARE stmt;

将来自两个表（多列和多行）的数据分组到一行中

1 个答案: