Question

我知道您不能使用for循环来创建具有数字图案名称的多个变量，但有什么方法可以通过某种循环简化以下代码行？否则它是一个非常长的文件，做得很少，我不喜欢这样！这是我的代码的缩短版本。

public DrawGrid(Context context, int[] binary) {...
sq00c = binary[0];  
sq01c = binary[1];  
sq02c = binary[2]; ...etc}

Rect sq00 = new Rect(); Paint sq00p = new Paint();  int sq00c;  
Rect sq01 = new Rect(); Paint sq01p = new Paint();  int sq01c;  
Rect sq02 = new Rect(); Paint sq02p = new Paint();  int sq02c; ...ect

protected void onDraw(Canvas canvas) {...
sq00.set(2*sqsize, line0, 3*sqsize, line0+sqsize);  sq00p.setColor(sq00c);  sq00p.setStyle(Paint.Style.FILL);   canvas.drawRect(sq00, sq00p);       
sq01.set(3*sqsize, line0, 4*sqsize, line0+sqsize);  sq01p.setColor(sq01c);  sq01p.setStyle(Paint.Style.FILL);   canvas.drawRect(sq01, sq01p);
sq02.set(4*sqsize, line0, 5*sqsize, line0+sqsize);  sq02p.setColor(sq02c);  sq02p.setStyle(Paint.Style.FILL);   canvas.drawRect(sq02, sq02p);
...etc}

上述三部分代码中的每一部分各有64次。有没有办法用循环简化它？感谢

Answer 1

尝试这种方式：

private int[] myInt;
private Rect[] myRect;
private Paint[] myPaint;

public DrawGrid(Context context, int[] binary) {
    myInt = binary;
    myRect = new Rect[myInt.length];
    myPaint = new Paint[myInt.length];

    for (int i = 0; i < myInt.length; i++) {
        //Put Rect parameters here, you have to take advantage of the "i" variable 
        myRect[i] = new Rect();

        myPaint[i] = new Paint();
        myPaint[i].setColor(myInt[i]);
        myPaint[i].setStyle(Paint.Style.FILL);
    }
}

protected void onDraw(Canvas canvas) {
    for (int i = 0; i < myRect.length; i++) { // < not >
        canvas.drawRect(myRect[i], myPaint[i]);
    }
}

Answer 2

保留一个Rects，Paints和int数组（或者更好的是，将它们全部放在一个漂亮的封装对象中并保留一个数组）并在循环中初始化它们。

Answer 3

例如，试试这个：

Rect[] rects=new Rect[SIZE];

并查看此link

使用for循环加速定义变量Java Android

3 个答案: