我在网格视图上有30张图像(每行3张图像)。如果用户选择第20张图像并转到下一个屏幕然后返回,那么我想要关注该位置。我使用了以下代码行,它适用于前8行,但在最后2行中它不会滚动。请帮忙。
gridview.setSelection(position);
gridview.requestFocusFromTouch();
gridview.setSelection(position);
由于
答案 0 :(得分:14)
原因是您的视图将在适配器中重用。
public class ImageAdapter extends BaseAdapter {
private Context context;
private final String[] someprivatevariable;
public ImageAdapter(Context context, String[] mobileValues) {
// Your boring constructor
}
public View getView(int position, View convertView, ViewGroup parent) {
LayoutInflater inflater = (LayoutInflater) context
.getSystemService(Context.LAYOUT_INFLATER_SERVICE);
View gridView;
// REUSE VIEW IF NOT NULL CODE
if (convertView == null) {
.....
.....
you generally create your view here
} else {
gridView = (View) convertView;
}
return gridView;
}
}
如果您的视图被强制不重用,那么您可以通过保存此值来滚动显示
int index = gridview.getFirstVisiblePosition();
并按
恢复该值gridview.smoothScrollToPosition(int index)
答案 1 :(得分:7)
你可以尝试这样的事情。我希望这对你有用..
选择发生时,请保存位置
int index = gridview.getFirstVisiblePosition();
当你回到gridview然后你可以试试这个
gridview.smoothScrollToPosition(int index)
答案 2 :(得分:0)
对我有用的解决方案是组合Monali和Sreedev的代码(谢谢Monali和Sreedev):
private int gridviewVerticalPositionWhenThumbnailTapped;
...
// save vertical position of gridview screen, will use to re-find this location if user follows a usre and gridview gets redrawn
gridviewVerticalPositionWhenThumbnailTapped = gridview.getFirstVisiblePosition();
稍后在app ...
// scroll gridview to vertical position pre user tap follow
gridview.setSelection(gridviewVerticalPositionWhenThumbnailTapped);