循环通过嵌套数组

时间:2013-04-03 01:12:37

标签: javascript

var map = [
        ["Blank", "Blank", "Blank"],
        ["Blank", "Player", "Blank"],
        ["Blank", "Blank", "Blank"]
];

我在循环数组时遇到问题。这里主要是这个功能。假设在矩阵内将“播放器”向下移动一个。

当玩家位置在顶部时,我尝试“玩家”的所有内容总是会下降到最底行。我也遇到了奇怪的错误问题。有时我根本不会改变代码(或者至少我认为是这样)。然后代码将不会有这个问题,然后它将再次出现。现在我也无法让“玩家”向左移动到中间。我将在最后展示该功能的代码。感谢您的帮助。

function moveDown() {
        for (y = map.length - 1; y >= 0 ; y--) {
            for (x = map[y].length - 1; x >= 0; x--) {
                var posX = map[y].indexOf("Player");

                if (posX > -1 && y == 0) {
                    map[1].splice(posX, 1,"Player");
                    map[y].splice(posX, 1,"Blank");
                    return;
                } else if (posX > -1 && y == 1) {
                    map[2].splice(posX, 1,"Player");
                    map[y].splice(posX, 1,"Blank");
                    return;
                } else if (posX > -1 && y == 2) {
                    return;
                }
            }
        }

    }

这是我的所有代码。如果你没有时间,请不要全部阅读。我现在的主要问题是使用moveDown()函数。 (我认为)

var map = [
        ["Blank", "Blank", "Blank"],
        ["Blank", "Player", "Blank"],
        ["Blank", "Blank", "Blank"]
];

var run = true;

menu();
printLoop(map);


while (run) {
    var input = prompt();

    if (input == "left") {
        movePlayer("left");
    } else if (input == "right") {
        movePlayer("right");
    } else if (input == "up") {
        movePlayer("up");
    } else if (input == "down") {
        movePlayer("down");
    }

    switch (input) {
      case "menu":
        menu(); break;
      case "quit": 
        run = false; break;
    }
    menu();
    printLoop(map);
}


function movePlayer(direction) {
    for (y=0; y<map.length; y++) {
        var playerPos = map[y].indexOf("Player");

        if (movableRight(playerPos)) {
            if (direction == "right") {
                map[y].splice(playerPos, 1,"Blank");
                map[y].splice(playerPos + 1, 1,"Player");
            }
        } else if (movableLeft(playerPos)) {
            if (direction == "left") {
                map[y].splice(playerPos, 1,"Blank");
                map[y].splice(playerPos - 1, 1,"Player");
            }
        }

        if (direction == "up") {
            moveUp();
        } else if (direction == "down") {
            moveDown();
        }

    }

}

/*function getX(obj) {
    for (x = 0; x < map.length; x++) {
        for (y = 0; y < map[x].length; y++) {
            if (map[x][y] == obj) {
                return x;
            }
        }
    }
}

function getY(obj) {
    for (x = 0; x < map.length; x++) {
        for (y = 0; y < map[x].length; y++) {
            if (map[x][y] == obj) {
                return y;
            }
        }
    }
}*/

function movableLeft(pos) {
    if (pos <= 0) {
        console.log(pos + "<= 0");
        return false;
    } else if (pos > map.length - 1) {
        console.log(pos + "> map.length - 1");
        return false;
    } else {
        console.log(pos + "true");
        return true;
    }
}

function movableRight(pos) {
    if (pos < 0) {
        return false;
    } else if (pos >= map.length - 1) {
        return false;
    } else {
        return true;
    }
}

function moveUp() {
    for (y = 0; y < map.length; y++) {
        for (x = 0; x < map[y].length; x++) {
            var posX = map[y].indexOf("Player");
                if(posX > -1) {
                    switch (y) {
                        case 1:
                            map[0].splice(posX, 1,"Player");
                            map[y].splice(posX, 1,"Blank");
                            break;
                        case 2:
                            map[1].splice(posX, 1,"Player");
                            map[y].splice(posX, 1,"Blank");
                }
            }
        }   
    }

}

function moveDown() {
    for (y = map.length - 1; y >= 0 ; y--) {
        for (x = map[y].length - 1; x >= 0; x--) {
            var posX = map[y].indexOf("Player");

            if (posX > -1 && y == 0) {
                map[1].splice(posX, 1,"Player");
                map[y].splice(posX, 1,"Blank");
                return;
            } else if (posX > -1 && y == 1) {
                map[2].splice(posX, 1,"Player");
                map[y].splice(posX, 1,"Blank");
                return;
            } else if (posX > -1 && y == 2) {
                return;
            }
        }
    }

}


function printLoop(array) {
    var line0 = "";
    var line1 = "";
    var line2 = "";

    for (y = 0; y < array.length; y++) {
        for (x = 0; x < array[y].length; x++) {
            switch (y) {
                case 0:
                    line0 += array[y][x] + ", "; break;
                case 1:
                    line1 += array[y][x] + ", "; break;
                case 2:
                    line2 += array[y][x] + ", "; break;
            }
        }
    }
    console.log(" ");
    console.log(line0);
    console.log(line1);
    console.log(line2);
    console.log(" ");

}

function menu() {
    console.log("===============================");
    console.log("up - down - right - left - quit");
    console.log("===============================");
}

1 个答案:

答案 0 :(得分:2)

除非我误解你的问题,否则你的事情过于复杂。这就是你所需要的:

function moveDown() {
    for (y = 0; y < map.length; y++) {
        var posX = map[y].indexOf("Player");
        if (posX < 0) continue;
        if ( y == map.length-1 ) break;

        map[y][posX] = "Blank";
        map[y+1][posX] = "Player";
        break;
    }
}

遍历顶级数组,直到找到包含播放器的行。然后,一旦你找到了玩家,如果它已经在底部你已经完成了。否则,使用"Blank"覆盖它,并使用"Player"覆盖下一行中的相应位置。