Question

我有NSMutableArray个AdDetail类的对象，这些对象包含一些属性（例如adId，adTitle，adPrice ......等）。我想只删除那些adID = 0的对象。我怎么能这样做？

Answer 1

或许更优雅的东西就足够了？

[array removeObjectsInArray:[array filteredArrayUsingPredicate:[NSPredicate predicateWithFormat:@"adID == 0"]]];

Answer 2

使用谓词

NSArray *filtered=[array filteredArrayUsingPredicate:[NSPredicate predicateWithFormat:@"(adId == 0)"]];

使用fastEnumeration：

NSMutableArray *newArray=[NSMutableArray new];
for(AdDetail adDetailObj in array){
    if(![[adDetailObj adId] isEqualToString:@"0"]){ //if these are strings, if NSInteger then directly compare using ==
       newArray[newArray.count]=adDetailObj;
   }
}

现在newArray包含id=0

以外的所有对象

Answer 3

NSMutableArray *newArray = [NSMutableArray arrayWithArray:yourArray];

for (int i = 0; i < yourArray.count; i++)
{
     AdDetail *obj = (AdDetail *)[yourArray objectAtIndex:i];
     if (obj.adID == 0)
         [newArray removeObjectAtIndex:i];
}
yourArray = [newArray mutableCopy];

Answer 4

for(i=0; i < myArray.count; i++)
{
  myClass = [myArray objectAtIndex:i];
  if([myClass.adID isEqualtoString:"0"])// if it it int/NSInteger the write myClass.adID==0
  {
            [myArray removeObjectAtIndex:i];
      i--;
  }
}

Answer 5

使用以下代码：

int count = array.count;
for(i=0;i<count;i++){

     ADetail *adetail = [array objectAtIndex:i];
     if(adetail.adID = 0){

         [array removeObjectAtIndex:i];
          i--;

     }
     count = array.count;
}

Answer 6

predicate = @"adID == 0";
newArray = [theArray filterUsingPredicate:aPredicate]

从NSMutableArray中删除某些对象

6 个答案: