Sed用特殊字符替换字符串

Question

我正在尝试用linux中的文件中的特殊字符替换下面指示的字符串。我尝试在每个特殊字符前面使用反斜杠，但是会出错。必须遗漏一些东西。我如何实现以下目标。提前致谢：

filter = [ "a/sda[0-9]*$/",  "r/sd.*/" ]   ---> Replace this line with below line

filter = [ "a/sda[0-9]*$/", "a/sdb[0-9]*$/", "r/sd.*/" ]

Answer 1

对于你的例子，这工作

sed 's@",@", "a/sdb[0-9]*$/",@' 

输出：

kent$  echo 'filter = [ "a/sda[0-9]*$/",  "r/sd.*/" ]'|sed 's@",@", "a/sdb[0-9]*$/",@'                                                         
filter = [ "a/sda[0-9]*$/", "a/sdb[0-9]*$/",  "r/sd.*/" ]

Answer 2

使用awk和列策略：

$ awk '{$3=$3 "a/sdb[0-9]*$/\042, "; print}' file.txt
filter = [a/sdb[0-9]*$/",  "a/sda[0-9]*$/", "r/sd.*/" ]