我正在尝试创建一个使用多个端口的服务器，因此可以轻松地发送和接收不同的数据和信息，但在我的doInBackground方法中，我的代码卡在了socket.receive上， 这是我的代码
while( run )
{
//GameServerID
try
{
if(gameServerID == null)
{
gameServerID = new DatagramSocket( portID );
}
//try to receive data
byte[] buf = new byte[256];
DatagramPacket packet = new DatagramPacket( buf, buf.length );
try
{
Log.d(TAG, "Wait for something to connect");
gameServerID.receive( packet ); <--GETS STUCK HERE
}
catch (IOException e)
{
Log.d(TAG, "Error with receiving data");
e.printStackTrace();
}
String data = new String( buf, 0, packet.getLength() );
Log.d(TAG, data);
//Send out the ID to the client
byte[] bufer = new byte[256];
//Send a message "connect" to the host
String msg = Integer.toString( players );
players = players + 1;
bufer = msg.getBytes();
InetAddress address;
//Default ip address of the host
address = packet.getAddress();
DatagramPacket p = new DatagramPacket( bufer, bufer.length , address, portID );
//Send packet
gameServerID.send( p );
addresses.add( address );
}
catch (SocketException e)
{
Log.d(TAG, "Error with socket");
e.printStackTrace();
}
//Listen for a client to connect
catch (IOException e)
{
Log.d(TAG, "Error with I/O");
e.printStackTrace();
}
//GameServerPositions
try
{
Log.d(TAG, "Run the gamePositions code");
if(gamePositions == null)
{
gamePositions = new DatagramSocket( portPos );
}
//Receive position
//try to receive data
byte[] buf = new byte[256];
DatagramPacket packet = new DatagramPacket( buf, buf.length );
try
{
gamePositions.receive( packet );
}
catch (IOException e)
{
Log.d(TAG, "Error with receiving data");
e.printStackTrace();
}
String data = new String( buf, 0, packet.getLength() );
Log.d(TAG, data);
String[] pos = data.split(":");
for(int i = 0;i<pos.length;i++)
{
Log.d(TAG, pos[i]);
}
xValues[ Integer.parseInt( pos[0] ) ] = Integer.parseInt( pos[1] );
yValues[ Integer.parseInt( pos[0] ) ] = Integer.parseInt( pos[2] );
}
catch (SocketException e)
{
Log.d(TAG, "Error with socket");
e.printStackTrace();
}
//Listen for a client to connect
catch (IOException e)
{
Log.d(TAG, "Error with I/O");
e.printStackTrace();
}
//GameServerSendPos
try
{
Log.d(TAG, "Run the gamePositionsSend code");
String data = "";
if( gameSendPos == null )
{
gameSendPos = new DatagramSocket( portSend );
}
//create the string ready to be sent out
for(int i = 0; i < 8; i++)
{
if(xValues[i] >= 0)
{
data += i + ":" + xValues[i] + ":" + yValues[i] + ":";
}
}
byte[] bufer = new byte[256];
bufer = data.getBytes();
DatagramPacket p = null;
for(int i = 0;i < addresses.size(); i++)
{
if( addresses.get(i) != null )
{
p = new DatagramPacket( bufer, bufer.length , addresses.get(i), portSend );
gameSendPos.send( p );
}
}
}
catch (SocketException e)
{
// TODO Auto-generated catch block
e.printStackTrace();
}
catch (IOException e)
{
// TODO Auto-generated catch block
e.printStackTrace();
}
}
我可以做些什么来阻止它被卡住，或者经过漫长的等待，只是为了跳过它？只是为了获得更多信息，当第一个客户端连接时，代码工作正常，直到它再次到达顶部然后socket.received刚刚堵塞...
帆布
更新
我已将我的代码更改为3个不同的类，我在我的服务器中启动它们，而循环就像这样
while( run )
{
if(start == true)
{
gsID.doInBackground( );
addresses = gsID.addresses;
gsPos.addresses = addresses;
gsPos.doInBackground( );
gsSendPos.addresses = addresses;
gsSendPos.positions = gsPos.positions;
gsSendPos.doInBackground( );
start = false;
}
else
{
addresses = gsID.addresses;
gsPos.addresses = addresses;
gsSendPos.addresses = addresses;
gsSendPos.positions = gsPos.positions;
}
}
但它仍然再次卡在gameServerID接收方法上。
我只是将我的所有类更改为线程，并且效果更好，但在更新版本的android 4.0+线程中无法从UI中使用，但我不确定如何从UI中启动它们？
答案 0 :(得分：2)
来自DatagramSocket.receive的Javadoc：
此方法将一直阻塞，直到收到数据报为止
因此，您的代码“卡住”，因为它正在等待数据包到达。这意味着连接到此服务器/端口的客户端尚未发送另一个数据包，因此套接字被设计阻塞。
传统上，如果您想同时收听多个端口，您有两个选择：