Question

我知道这不是“它应该工作的方式”，但仍然是：如果你有两个DateTime对象，那么减去它们的好方法是什么？将它们转换为Date对象？

DateTime start = new DateTime();
System.out.println(start + " - doing some stuff");

// do stuff

DateTime end = new DateTime();
Period diff = // end - start ???
System.out.println(end + " - doing some stuff took diff seconds");

Answer 1

期间有a constructor that takes two ReadableInstant instances：

Period diff = new Period(start, end);

（ReadableInstant是由DateTime以及其他类实现的接口。）

Answer 2

从您的示例中，您似乎想要以秒为单位的差异this should help：

Seconds diff = Seconds.secondsBetween(start, end);

Answer 3

这有帮助吗？ http://joda-time.sourceforge.net/key_period.html 它显示了以下示例

DateTime start = new DateTime(2004, 12, 25, 0, 0, 0, 0);
DateTime end = new DateTime(2006, 1, 1, 0, 0, 0, 0);

// period of 1 year and 7 days
Period period = new Period(start, end);

// calc will equal end
DateTime calc = start.plus(period);

// able to calculate whole days between two dates easily
Days days = Days.daysBetween(start, end);

Answer 4

取决于您想要获得的精确度。您应该检查org.joda.time包并检查帮助程序类，例如Hours，Days等。

Answer 5

我认为您可以使用this构造函数创建Period，该构造函数需要两个DateTime个对象。

如何减去两个joda日期时间？

5 个答案: