Question

我的文件包含这些数字 123.4 23.7 89.2 ...... 45.8
...

8列和1024行，我希望逐行读取此文件，并将每行放在double数组中以获取此行中的最小数字，并将此最小数字放在大小为1024的数组中。

我在c＃...

中尝试了这段代码

 static void Main(string[] args)
    {
        string line;
        double[] row = new double[8];
        double[] minimum = new double[1024];
        // Read the file and display it line by line.
        System.IO.StreamReader file =
           new System.IO.StreamReader("c:\\test.txt");

        for (int k = 0; k < 1024; k++)
        {
            while ((line = file.ReadLine()) != null )
            {

                string[] numbers = new string[8];
                int numCount = 0;
                for (int i = 0; i < line.Length; i++)
                {
                    if (line[i] != ' ')
                    {
                        numbers[numCount] = "";
                        while (line[i] != ' ')
                        {
                            numbers[numCount] += line[i];
                            i++;

                        }
                        numCount++;

                    }
                }
                for (int i = 0; i < 8; i++)
                {
                    row[i] = Convert.ToDouble(numbers[i]);
                }

                double min = row[0];
                for (int j = 0; j < 8; j++)
                {
                    if (row[j] <= min)
                        min = row[j];

                }
                minimum[k] = min;

            }

        }
        Console.WriteLine("The array contain:");
        for (int i = 0; i < 1024; i++)
            Console.WriteLine(minimum[i]);

           file.Close();


        // Suspend the screen.
        Console.ReadLine();
    }

Answer 1

有几种方法可以简化您的代码 - File.ReadLines，String.Split和LINQ Select。结果代码可能类似于：

var listOfArraysOfDouble = File.ReadLines(fileName)
    .Select(row => 
         row.Split((string[]) null, StringSplitOptions.RemoveEmptyEntries)
           .Select(columnValue => double.Parse(columnValue))
           .ToArray()
     );

如何处理数字文件c＃

1 个答案: