检查数组是否包含C中另一个数组的所有数组值

时间:2013-04-04 20:54:51

标签: c arrays if-statement contains

我试图创建一个程序来检查一个数组是否包含来自另一个数组的所有数组值。所以,如果这是真的,程序将使用一个值返回1。如果不是,它将返回0(我将其命名为p)。我虽然没有制作那个节目。你能帮我吗?

1 个答案:

答案 0 :(得分:1)

#include <stdio.h>

int isSubset(int arr1[], int arr2[], int m, int n)
{
    int i = 0;
    int j = 0;
    for (i=0; i<n; i++)
    {
        for (j = 0; j<m; j++)
        {
           if(arr2[i] == arr1[j])
              break;
        }

        /* If the above inner loop was not broken at all then
           arr2[i] is not present in arr1[] */
        if (j == m)
           return 0;
    }

    /* If we reach here then all elements of arr2[] 
      are present in arr1[] */
    return 1;
}

int main()
{
    int arr1[] = {11, 1, 13, 21, 3, 7};
    int arr2[] = {11, 2, 7, 1};

    int m = sizeof(arr1)/sizeof(arr1[0]);
    int n = sizeof(arr2)/sizeof(arr2[0]);

    if(isSubset(arr1, arr2, m, n))
      printf("arr2[] is subset of arr1[] ");
    else
      printf("arr2[] is not a subset of arr1[]");      

    getchar();
    return 0;
}



Ideone链接并运行http://ideone.com/4u9oQm

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