你好我想问一个问题,现在我开始使用搜索引擎了,你能否建议一些功能或方法如何启动或用什么来用数据库用户通过用户名制作搜索引擎.It可以从另一个单词中的一个符号中搜索“k”,然后搜索以用户名“k”开头的所有用户名。 例: http://postimg.org/image/sg84ny3w3/
尝试:
private function Search()
{
global $database;
if(isset($_POST['s'])) {
if($_POST['s'] == '1' || $_POST['s'] == '2' || $_POST['s'] == '3')
$type = $_POST['s'];
$database->getSearchData($type, $_POST['xs']);
}
else if(!preg_match("/[^0-9A-Za-z]/", $_POST['xs'])){
$error = "You entered invalid data";
}
return false;
}
HTML:
<div id="content">
<div style="padding:20px">
<?echo $error;?>
<form action="index.php?mod=highscore&t=search" method="POST" accept-charset="utf-8">
<div class="title_box"><div class="title_inner">
What are you searching for? </div></div>
<div class="title2_box"><div class="title2_inner">
<p>
<table width="80%">
<tr>
<td><input type="radio" name="s" value="1"></td>
<td>Player</td>
</tr>
<tr>
<td><input type="radio" name="s" value="2"></td>
<td>Guild (Name)</td>
</tr>
<tr>
<td><input type="radio" name="s" value="3"></td>
<td>Guild (Guild Tag)</td>
</tr>
<tr>
<td>Text:</td>
<td colspan="2"><input type="text" name="xs" size="30" maxlength="30" value=""></td>
</tr>
<tr>
<td colspan="3"><input type="submit" value="Search" class="button3" name="search"></td>
</tr>
</table>
</p>
</form>
</div></div>
<br />
<?if($functions->Search() == false) {?>
<div class="title_box"><div class="title_inner">
Results </div></div>
<div class="title2_box"><div class="title2_inner">
<p>
<table width="50%">
<tr>
<td>Player</td>
<td>Level</td>
<td>Total honour</td>
</tr>
<tr><td class="f" colspan="2">No results</td></tr></table> </p>
</div></div>
<?} else {?>
<div class="title_box"><div class="title_inner">
Results </div></div>
<div class="title2_box"><div class="title2_inner">
<p>
<table width="50%">
<tr>
<td>Player</td>
<td>Level</td>
<td>Total honour</td>
</tr>
<tr><td class="f" colspan="2"><?$functions->Search();?></td></tr></table> </p>
</div></div>
<?}?>
</div>
<script type='text/javascript'>var tickerArray = new Array();function doTicker(){
n=new Date();
if (tickerArray.length > 0)
{
for (i = 0; i < tickerArray.length; i++)
{
if (isNaN(document.getElementById(tickerArray[i]["id"])))
{
var e = document.getElementById(tickerArray[i]["id"]);
s = tickerArray[i]["sek"];
m = 0;
h = 0;
d = 0;
if (s < 0)
e.innerHTML = "---";
else
{
var timeTXT = s + " s";
if (s > 59)
{
m = Math.ceil(s / 60);
s = s-m * 60;
timeTXT = m + " m";
}
if (m > 59)
{
h = Math.ceil(m / 60);
m = m - h * 60;
timeTXT = h + " h";
}
if (h > 24)
{
d = Math.ceil(h / 24);
h = h-d * 24;
timeTXT = d + " d";
}
e.innerHTML = timeTXT;
tickerArray[i]["sek"]--;
}
}
}
window.setTimeout("doTicker();",999);
}
}doTicker();</script>
</div>
答案 0 :(得分:1)
SELECT * FROM users where username like 'k%'
将返回用户名以k
SELECT * FROM user where username LIKE '%k%'
将返回包含字符k
的所有用户记录http://dev.mysql.com/doc/refman/5.0/en/string-comparison-functions.html#operator_like
答案 1 :(得分:0)
使用这个简单的代码: http://www.simonerodriguez.com/ajax-form-submit-example/
删除表单上的“on_submit”操作。
在文本框中添加属性: onKeyDown =“xmlhttpPost('response_ajax.php,'MyForm','MyResult',''); return false;”
第三个参数“MyResult”将是您在php文件中输出的任何内容,因此它将被放置在名为“MyResilt”的div中 div id =“MyResult”&gt; / DIV&GT;
您的php文件可以输出如下内容: echo“$ Result”
这将做你想要的。