长期在Java中被视为数组中的int

时间:2013-04-08 19:19:13

标签: java arrays int long-integer

我已经将一个变量定义为long,当我尝试在我的数组中使用它时,它会不断抛出一个错误,说我的值超出了int范围。好吧,不开玩笑,这很长,我把它定义为一个。

以下是我的代码。在第二课,LoanOfficer,你会发现第二个申请人比尔盖茨,其年收入为3,710,000,000,这就是错误。

public class Applicant {
    private String name;
    private int creditScore;
    private long annualIncome;
    private int downPayment;
    private boolean status;

    public Applicant(String name, int creditScore, long annualIncome,
            int downPayment) {
        this.name = name;
        this.creditScore = creditScore;
        this.annualIncome = annualIncome;
        this.downPayment = downPayment;
        this.status = false;
    }

    public String getName() {
        return name;
    }

    public int getCreditScore() {
        return creditScore;
    }

    public long getAnnualIncome() {
        return annualIncome;
    }

    public int getDownPayment() {
        return downPayment;
    }

    public void setStatus(boolean status) {
        this.status = status;
    }

    public boolean isStatus() {
        return status;
    }
}

public class LoanOfficer {
    public static void main(String[] args) {
        Applicant[] applicants = {
                new Applicant("MC Hammer", 400, 25000, 5000),
                new Applicant("Bill Gates", 850, 3710000000, 500000),
                new Applicant("MC Hammer", 400, 25000, 5000),
                new Applicant("MC Hammer", 400, 25000, 5000), };
    }
}

3 个答案:

答案 0 :(得分:15)

对于被视为长号的数字,您需要L后缀:

new Applicant("Bill Gates", 850, 3710000000L, 500000)

如果缺少L后缀,编译器会将文字视为int

答案 1 :(得分:5)

您需要通过附加L

将3710000000指定为长文字
new Applicant("Bill Gates", 850, 3710000000L, 500000),

来自JLS

  

如果整数文字后缀为ASCII字母L或l(ell),则其长度为long;否则它是int

类型

答案 2 :(得分:2)

将3710000000更改为3710000000L。问题是如果没有L,Java会将其视为int