Question

我第一次真正尝试了一个python程序 - 一个猜字游戏。

我完成了大部分工作，但我仍然坚持最后一点

我想这样做，以便游戏在用户和AI转换之间来回交替，直到世界完全显露出来。到目前为止，我很好。在这一点上，我想让它成为玩家猜测正确的大多数字母赢得一个点。计算机主持人选择另一个单词并重新开始。第一个获得5分的玩家赢得了比赛。

我有一个在用户/ AI转换之间交替的while循环，但是一旦这个单词完全揭开，我就无法让它正常打破？之后，将userCorrectLetters的数量与aiCorrectLetters的数量进行比较并使用它来确定谁赢得该轮次的点数应该非常简单。

然后我假设整个事情应该进入一个不会中断的while循环，直到其中一个玩家达到5分。

我遇到的另一件事是如何禁止用户重新猜测已经解决的角色位置。

import random


#set initial values
player1points= 0
ai= 0
userCorrectLetters= []
aiCorrectLetters=[]
wrongLetters=[]
wrongPlace= []
correctLetters = []
endGame = False
allLetters = set(list('abcdefghijklmnopqrstuvwxyz'))
alreadyGuessed = set() 
userGuessPosition = 0
availLetters = allLetters.difference(alreadyGuessed)


#import wordlist, create mask
with open('wordlist.txt') as wordList:
    secretWord = random.choice(wordList.readlines()).strip()
print (secretWord)
secretWordLength = len(secretWord)








def displayGame():
    mask = '_'  * len(secretWord)
    for i in range (len(secretWord)):
        if secretWord[i] in correctLetters:
            mask = mask[:i] + secretWord[i] + mask [i+1:]
    for letter in mask:
        print (letter, end='')
    print (' ')
    print ('letters in word but not in correct location:', wrongPlace)
    print ('letters not in word:', wrongLetters)



    ##asks the user for a guess, assigns input to variable

def getUserGuess(alreadyGuessed):


    while True:
        print ('enter your letter')
        userGuess = input ()
        userGuess= userGuess.lower()
        if len(userGuess) != 1:
            print ('please enter only one letter')
        elif userGuess in alreadyGuessed:
            print ('that letter has already been guessed. try again')
        elif userGuess not in 'abcdefjhijklmnopqrstuvwxyz':
            print ('only letters are acceptable guesses. try again.')
        else:
            return userGuess

def newGame():
    print ('yay. that was great. do you want to play again? answer yes or no.')
    return input().lower().startswith('y')

def userTurn(wrongLetters, wrongPlace, correctLetters):
    print ('\n')

    displayGame ()
    print ('which character place would you like to guess. Enter number?')
    userGuessPosition = input ()
    if userGuessPosition not in ('123456789'):
        print ('please enter a NUMBER')
        userGuessPosition = input()
    slice1 = int(userGuessPosition) - 1  


    ##player types in letter
    guess = getUserGuess(wrongLetters + correctLetters)
    if guess== (secretWord[slice1:int(userGuessPosition)]):
        print ('you got it right! ')
        correctLetters.append(guess)
        userCorrectLetters.append(guess)
        displayGame()

    elif guess in secretWord:
            wrongPlace.append(guess) 
            print ('that letter is in the word, but not in that position')
            displayGame()

    else:
            wrongLetters.append(guess)
            print ('nope. that letter is not in the word')
            displayGame()




def aiTurn(wrongLetters,wrongPlace, correctLetters):
    print ('\n')
    print ("it's the computers turn")

    aiGuessPosition = random.randint(1, secretWordLength)

    aiGuess=random.sample(availLetters, 1)
    print ('the computer has guessed', aiGuess, "in position", + aiGuessPosition)
    slice1 = aiGuessPosition - 1
    if str(aiGuess) == (secretWord[slice1:userGuessPosition]):
            correctLetters.append(aiGuess)
            aiCorrectLetters.append(aiGuess)
            print ('this letter is correct ')
            return 
    elif str(aiGuess) in secretWord:
            wrongPlace.append(aiGuess)
            print ('that letter is in the word, but not in that position')
            return

    else:
            wrongLetters.append(aiGuess)
            print ('that letter is not in the word')
            return



wordSolved = False 
while wordSolved == False:

    userTurn(wrongLetters, wrongPlace, correctLetters)
    aiTurn(wrongLetters, wrongPlace, correctLetters)
    if str(correctLetters) in secretWord:
        break

Answer 1

问题在于：

if str(correctLetters) in secretWord:

您可能希望str(['a', 'b', 'c'])返回'abc'，但事实并非如此。它返回"['a', 'b', 'c']"。您应该用以下内容替换该行：

if "".join(correctLetters) in secretWord:

您的代码还有一个问题，除了这个问题：假设正确的单词是foobar。如果用户猜到前5个字母，但按相反的顺序排列，则correctLetters将为['a', 'b', 'o', 'o', 'f']，而行if "".join(correctLetters) in secretWord:将评估为False，因为'aboof'是'foobar'不在if "".join(correctLetters) in secretWord:。

您可以将if len(correctLetters) > 4:替换为：

来解决该问题

secretWord

基本上，一旦用户猜出5个正确的字母，这将结束程序的执行。无需检查字母是否在userTurn中，因为您已在{{1}}函数中执行此操作。

Answer 2

您正在将列表correctLetters的字符串表示与字符串secretWord进行比较。例如：

>>> secretWord = 'ab'
>>> correctLetters = ['a','b']
>>> str(correctLetters)
"['a', 'b']"
>>> str(correctLetters) in secretWord
False

尝试将由正确字母组成的字符串与密码字词进行比较：

>>> ''.join(correctLetters) == secretWord
True

python字母猜谜游戏

2 个答案: