Question

您好我有以下代码对我的数据进行分页，我也有一些复选框可以调整显示的结果。我遇到的问题是，当我在1页上有所有内容时它工作正常，但当结果分页时，分页将不会显示在底部，它只显示14个结果，就是这样。这是我的代码

 if(isset($_POST['criteria']) && !empty($_POST['criteria'])){ 
 foreach($_POST['criteria'] as $key=>$value){ 

 // Runs mysql_real_escape_string() on every value encountered.
 $clean_criteria = array_map('mysql_real_escape_string', $_REQUEST['criteria']);

 //get the function
 include ($_SERVER['DOCUMENT_ROOT'] .'/script/pagination-functions.php');    
 $page = (int) (!isset($_GET["page"]) ? 1 : $_GET["page"]);
 $limit = 14;
 $startpoint = ($page * $limit) - $limit;

// Convert the array into a string.
 $criteria = implode("','", $clean_criteria);
 if(!$query=mysql_query("SELECT * FROM mytable WHERE exercise IN ('$criteria') ORDER BY long ASC LIMIT {$startpoint} , {$limit}"))
 {
echo "Cannot parse query";
}
elseif(mysql_num_rows($query) == 0) {
echo "No records found";
}

while($row = mysql_fetch_assoc($query)) {

       echo "".$row['title'] ."<br>
             ".$row['description'] ."";
        }
         echo "<div class=\"new-pagination\">";
        echo pagination($statement,$limit,$page);
        echo "</div>";
    }
}

这是我的分页脚本

     function pagination($query, $per_page = 10, $page = 1, $url = '?'){    

    $query = "SELECT COUNT(*) as `num` FROM {$query}";
    $row = mysql_fetch_array(mysql_query($query));
    $total = $row['num'];
    $adjacents = "1"; 

    $page = ($page == 0 ? 1 : $page);  
    $start = ($page - 1) * $per_page;   

    $firstPage = 1;
    $prev = ($page == 1)?1:$page - 1; 

    $prev = $page - 1;                          
    $next = $page + 1;
    $lastpage = ceil($total/$per_page);
    $lpm1 = $lastpage - 1;


    $pagination = "";


    if($lastpage >  1)
    {   
        $pagination .= "<ul class=\"pagination1\">";

                if ($page == 1)
  {
  $pagination.= "<li><a class=\"inactive\">First</a></li>";
  $pagination.= "<li><a class=\"inactive\">Prev</a></li>"; 
  }
  else
   {
  $pagination.= "<li><a href=\"{$url}&page=$firstPage\">First</a></li>";
  $pagination.= "<li><a href=\"{$url}&page=$prev\">Prev</a></li>"; 
  }



                $pagination .= "<li class=\"details\">Page $page of $lastpage</li>";
        if ($lastpage < 7 + ($adjacents * 2))

        {   
            for ($counter = 1; $counter <= $lastpage; $counter++)
            {
        if ($counter == $page)
        $pagination.= "<li><a class=\"current\">$counter</a></li>";
        else
         $pagination.= "<li><a href=\"{$url}&page=$counter\">$counter</a></li>";                    
            }
        }
        elseif($lastpage > 5 + ($adjacents * 2))
        {
         if($page < 1 + ($adjacents * 2))       
        {
         for ($counter = 1; $counter < 4 + ($adjacents * 2); $counter++)
        {
        if ($counter == $page)
        $pagination.= "<li><a class=\"current\">$counter</a></li>";
        else
        $pagination.= "<li><a href=\"{$url}&page=$counter\">$counter</a></li>";                 
        }
        $pagination.= "<li class=\"dot\">... </li>";
        $pagination.= "<li><a href=\"{$url}&page=$lpm1\">$lpm1</a></li>";
        $pagination.= "<li><a href=\"{$url}&page=$lastpage\">$lastpage</a></li>";       
        }
        elseif($lastpage - ($adjacents * 2) > $page && $page > ($adjacents * 2))
        {
        $pagination.= "<li><a href=\"{$url}&page=1\">1</a></li>";
        $pagination.= "<li><a href=\"{$url}&page=2\">2</a></li>";
        $pagination.= "<li class=\"dot\">...</li>";
        for ($counter = $page - $adjacents; $counter <= $page + $adjacents; $counter++)
                {
        if ($counter == $page)
        $pagination.= "<li><a class=\"current\">$counter</a></li>";
        else
        $pagination.= "<li><a href=\"{$url}&page=$counter\">$counter</a></li>";                 
        }
        $pagination.= "<li class=\"dot\">..</li>";
        $pagination.= "<li><a href=\"{$url}&page=$lpm1\">$lpm1</a></li>";
        $pagination.= "<li><a href=\"{$url}&page=$lastpage\">$lastpage</a></li>";       
            }
            else
            {
        $pagination.= "<li><a href=\"{$url}&page=1\">1</a></li>";
        $pagination.= "<li><a href=\"{$url}&page=2\">2</a></li>";
        $pagination.= "<li class=\"dot\">..</li>";
        for ($counter = $lastpage - (2 + ($adjacents * 2)); $counter 
                 $lastpage;             
                 $counter++)
        {
        if ($counter == $page)
        $pagination.= "<li><a class=\"current\">$counter</a></li>";
                    else
        $pagination.= "<li><a href=\"{$url}&page=$counter\">$counter</a></li>";                 
                }
            }
        }

        if ($page < $counter - 1){ 
            $pagination.= "<li><a href=\"{$url}&page=$next\">Next</a></li>";
            $pagination.= "<li><a href=\"{$url}&page=$lastpage\">Last</a></li>";
        }else{
            $pagination.= "<li><a class=\"inactive\">Next</a></li>";
            $pagination.= "<li><a class=\"inactive\">Last</a></li>";
        }
        $pagination.= "</ul>\n";        
    }


    return $pagination;
}

我还需要存储所选复选框的数据，以便为下一页保留结果。如果有人能给我任何帮助或指出我正确的方向，我会非常感激。

Answer 1

提供代码已完成，$statement变量未定义，因此pagination函数中的SQL语法无效，因为$query为空。

另请注意，在最后一个for循环的第三个表达式中没有运算符。所以代码甚至都没有编译。

您是否在PHP中启用了警告？可能不是，否则你会得到一些，他们想引导你去解决。请启用它们并分享。你会变得更好。

如何使用php和分页的多个复选框

1 个答案: