似乎无法使用bash来实现此功能

时间:2013-04-13 00:15:44

标签: bash

# define some variables for later
date=`date`
usr=`whoami`

# define usage function to echo syntax if no args given
usage(){
    echo "error: filename not specified"
    echo "Usage: $0 filename directory/ directory/ directory/"
    exit 1
}

# define copyall function
copyall() {
    # local variable to take the first argument as file
    local file="$1" dir
    # shift to the next argument(s)
    shift

    # loop through the next argument(s) and copy $file to them
    for dir in "$@"; do
        cp -R "$file" "$dir"
    done
}

# function to check if filename exists
# $f -> store argument passed to the script
file_exists(){
    local f="$1"
    [[ -f "$f" ]] && return 0 || return 1
}
# call usage() function to print out syntax
[[ $# -eq 0 ]] && usage

这是我无法弄清楚的

# call file_exists() and copyall() to do the dirty work
if ( file_exists "$1" ) then
    copyall

我还想知道如何采用下一个回声部分并将其压缩到一行。而不是1美元然后转移然后继续前进。也许把它分成一个数组?

    echo "copyall: File $1 was copied to"
    shift 
    echo "$@ on $date by $usr"
else
    echo "Filename not found"
fi

exit 0

2 个答案:

答案 0 :(得分:1)

在我看来,file_exists宏是多余的:

if [ -f "$1" ]
then copy_all "$@"
else echo "$0: no such file as $1" >&2; exit 1
fi

甚至只是:

[ -f "$1" ] && copy_all "$@"

答案 1 :(得分:0)

您可能只需要删除file_exists "$1"周围的括号,然后添加分号:

if file_exists "$1"; then
    copyall