如何从具有需要匹配临时表的条件的表中进行选择?

时间:2013-04-14 15:15:49

标签: mysql select temp-tables

我有两张桌子。一个包含文章,另一个包含价格报价。我正在尝试从文章表中选择[EAN],如果两个表中的维度匹配,则从引号表中选择price

以下是我正在玩的例子:

DROP TEMPORARY TABLE IF EXISTS haha;
CREATE TEMPORARY TABLE haha (
    tmp_kto VARCHAR(7) DEFAULT ''
    , tmp_kz VARCHAR(3) DEFAULT ''
    , tmp_preisliste VARCHAR(1) DEFAULT ''
    , tmp_eg VARCHAR(3) DEFAULT ''
    , tmp_length VARCHAR(3) DEFAULT ''
    , tmp_width VARCHAR(3) DEFAULT ''
    , tmp_price DECIMAL(10,2) DEFAULT 0.00
    ) ENGINE=MEMORY;

INSERT INTO haha (
    tmp_kz, tmp_kto, tmp_preisliste, tmp_eg, tmp_length, tmp_width, tmp_price
    ) VALUES (
    "000","4316134","I","520","150","200","14.95"
    );
INSERT INTO haha (
    tmp_kz, tmp_kto, tmp_preisliste, tmp_eg, tmp_length, tmp_width, tmp_price
    ) VALUES (
    "001","112233","L","520","150","200","17.95"
    );

匹配条件应为[EG][size]。对于size,我需要将相关大小子字段排除在字段之外(我认为没有其他方式 - 格式为例如050x250cm)。

SELECT ean, preis 
    FROM (
    SELECT  a.ean AS ean
           , h.tmp_price AS preis
    FROM articles AS a
    LEFT JOIN haha AS h
        ON h.tmp_eg = a.eg
        AND h.tmp_kz = "000"
        AND h.tmp_kto = "0000000"
        AND h.tmp_preisliste = "I"
        AND h.tmp_length = SUBSTRING(a.size,1,3)
        AND h.tmp_width = SUBSTRING(a.size,4,3)
) AS temp;

哪个不起作用。

问题:
我需要更改什么才能使其正常工作?

修改
第二个表看起来像这样:

CREATE TABLE `articles` (
    `id` INT(11) NOT NULL AUTO_INCREMENT,
    `ean` VARCHAR(35) NULL DEFAULT NULL,
    `size` VARCHAR(35) NULL DEFAULT NULL,
    `eg` VARCHAR(35) NULL DEFAULT NULL,
PRIMARY KEY (`id`),
)
COLLATE='latin1_swedish_ci'
ENGINE=InnoDB
AUTO_INCREMENT=1;

INSERT INTO articles (
    ean, size, eg
    ) VALUES (
    "1111111111111","150x200cm","520"
    );

INSERT INTO articles (
    ean, size, eg
    ) VALUES (
    "2222222222222","150x220cm","520"
    );

感谢您的帮助!

2 个答案:

答案 0 :(得分:1)

为什么你不这么简单地使用?

SELECT a.ean, h.tmp_price AS preis 
FROM articles AS a
LEFT JOIN haha AS h
    ON h.tmp_eg = a.eg
WHERE h.tmp_kz = "000"
    AND h.tmp_kto = "0000000"
    AND h.tmp_preisliste = "I"
    AND h.tmp_length = SUBSTRING(a.size,1,3)
    AND h.tmp_width = SUBSTRING(a.size,4,3)

答案 1 :(得分:0)

比思想容易:

    SELECT a.ean AS ean,
           h.tmp_price AS preis
    FROM articles AS a
    LEFT JOIN haha AS h
    ON h.tmp_eg = a.eg

    WHERE a.iln = "some_id"
    AND h.tmp_kz = "000"
    AND h.tmp_kto = "0000000"
    AND h.tmp_preisliste = "I"
    AND h.tmp_length = SUBSTRING(a.groesse,1,3)
    AND h.tmp_width = SUBSTRING(a.groesse,5,3)
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