Question

我正在尝试检查几个URL以查看它们是否在我进一步操作之前恢复正常，我在self.myList中有一个URL列表，然后通过httplib HTTP Connection运行这些URL以获取响应但是我从cmd中的httplib中得到了大量错误。

代码工作正常，因为我已经使用下面的代码进行了测试，它正确地返回并在wx.TextCtrl中设置值：

#for line in self.myList:
            conn = httplib.HTTPConnection("www.google.com")
            conn.request("HEAD", "/")
            r1 = conn.getresponse()
            r1 = r1.status, r1.reason
            self.urlFld.SetValue(str(r1))

当我从myList传递超过1个URL时，它似乎不起作用。

for line in self.myList:
            conn = httplib.HTTPConnection(line)
            conn.request("HEAD", "/")
            r1 = conn.getresponse()
            r1 = r1.status, r1.reason
            self.urlFld.SetValue(line + "\t\t" + str(r1))

我在cmd上遇到的错误是

Traceback (most recent call last):
File "gui_texteditor_men.py", line 96, in checkBtnClick
conn.request("HEAD", "/")
File "C:\Python27\lib\httplib.py", line 958, in request
self._send_request(method, url, body, headers)
File "C:\Python27\lib\httplib.py", line 992, in _send_request
self.endheaders(body)
File "C:\Python27\lib\httplib.py", line 954, in endheaders
self._send_output(message_body)
File "C:\Python27\lib\httplib.py", line 814, in _send_output
self.send(msg)
File "C:\Python27\lib\httplib.py", line 776, in send
self.connect()
File "C:\Python27\lib\httplib.py", line 757, in connect
self.timeout, self.source_address)
File "C:\Python27\lib\socket.py", line 553, in create_connection
for res in getaddrinfo(host, port, 0, SOCK_STREAM):
socket.gaierror: [Errno 11004] getaddrinfo failed

编辑，使用urlparse更新代码。我导入了urlparse。

for line in self.myList:
            url = urlparse.urlparse(line)
            conn = httplib.HTTPConnection(url.hostname)
            conn.request("HEAD", url.path)
            r1 = conn.getresponse()
            r1 = r1.status, r1.reason
            self.urlFld.AppendText(url.hostname + "\t\t" + str(r1))

带回溯，

C:\Python27\Coding>python gui_texteditor_men.py
Traceback (most recent call last):
File "gui_texteditor_men.py", line 97, in checkBtnClick
conn = httplib.HTTPConnection(url.hostname)
File "C:\Python27\lib\httplib.py", line 693, in __init__
self._set_hostport(host, port)
File "C:\Python27\lib\httplib.py", line 712, in _set_hostport
i = host.rfind(':')
AttributeError: 'NoneType' object has no attribute 'rfind'

我现在将www.google.com和www.bing.com放在.txt文件中，当它抛出此错误时。

编辑2 @ Aya，

由于2个URL之间的“\ n”，

看起来失败了。我以为我编写了它来删除带有.strip（）的“\ n”但似乎它没有任何效果。

Failed on u'http://www.google.com\nhttp://www.bing.com'
Traceback (most recent call last):
File "gui_texteditor_men.py", line 99, in checkBtnClick
conn.request("HEAD", url.path)
File "C:\Python27\lib\httplib.py", line 958, in request
self._send_request(method, url, body, headers)
File "C:\Python27\lib\httplib.py", line 992, in _send_request
self.endheaders(body)
File "C:\Python27\lib\httplib.py", line 954, in endheaders
self._send_output(message_body)
File "C:\Python27\lib\httplib.py", line 814, in _send_output
self.send(msg)
File "C:\Python27\lib\httplib.py", line 776, in send
self.connect()
File "C:\Python27\lib\httplib.py", line 757, in connect
self.timeout, self.source_address)
File "C:\Python27\lib\socket.py", line 553, in create_connection
for res in getaddrinfo(host, port, 0, SOCK_STREAM):
socket.gaierror: [Errno 11004] getaddrinfo failed

当我打开文件时，我又看了一下我的.strip（），

if dlg.ShowModal() == wx.ID_OK:
        directory, filename = dlg.GetDirectory(), dlg.GetFilename()
        self.filePath = '/'.join((directory, filename))
        self.fileTxt.SetValue(self.filePath)
        self.urlFld.LoadFile(self.filePath)
        self.myList = self.urlFld.GetValue().strip()

现在它的回溯错误“失败了”

由于

Answer 1

如果self.myList包含网址列表，则不能像在此处一样直接在HTTPConnection构造函数中使用它们。

for line in self.myList:
    conn = httplib.HTTPConnection(line)
    conn.request("HEAD", "/")

HTTPConnection构造函数只应传递URL的主机名部分，并且请求方法应该给出路径部分。您需要使用类似......

的内容来解析URL

import urlparse

for line in self.myList:
    url = urlparse.urlparse(line)
    conn = httplib.HTTPConnection(url.hostname)
    conn.request("HEAD", url.path)

<强>更新

您可以将代码更改为...

for line in self.myList:
    try:
        url = urlparse.urlparse(line)
        conn = httplib.HTTPConnection(url.hostname)
        conn.request("HEAD", url.path)
        r1 = conn.getresponse()
        r1 = r1.status, r1.reason
        self.urlFld.AppendText(url.hostname + "\t\t" + str(r1))
    except:
        print 'Failed on %r' % line
        raise

...并包含运行它的完整输出？

更新＃2

我不太确定self.fileTxt和self.urlFld应该做什么，但如果您只是从self.filePath读取行，则只需要......

if dlg.ShowModal() == wx.ID_OK:
    directory, filename = dlg.GetDirectory(), dlg.GetFilename()
    self.filePath = '/'.join((directory, filename))
    self.myList = [line.strip() for line in open(self.filePath, 'r').readlines()]

httplib python / wxpython。袜子流错误

1 个答案: