Question

我想禁用在引发异常时打印的堆栈跟踪。

Answer 1

环顾四周，我找到了以下解决方案/解决方法：

sys.tracebacklimit = 0

Answer 2

每当代码调用 logger.exception 方法时，都会自动打印堆栈跟踪。这是因为 exc_info 方法的 .exception 参数的默认值为 True。

查看源代码：

def exception(msg, *args, exc_info=True, **kwargs):
    """
    Log a message with severity 'ERROR' on the root logger, with exception
    information. If the logger has no handlers, basicConfig() is called to add
    a console handler with a pre-defined format.
    """
    error(msg, *args, exc_info=exc_info, **kwargs)

为了防止这种情况，您可以像这样将 exc_info=False 发送到 .exception 方法：

  try:
      raise Exception("Huston we have a problem!")
  except Exception as ex:
      logger.exception(f"Looks like they have a problem: {ex}", exc_info=False)

虽然这看起来可行，但强迫用户每次使用该方法时都写 exc_info=False 是不好的。因此，为了减轻程序员的负担，你可以给 .exception 方法打补丁，让它像一个普通的 .error 方法一样：

# somewhere in the start of your program
# money patch the .exception method
logger.exception = logger.error

  try:
      raise Exception("Huston we have a problem!")
  except Exception as ex:
      logger.exception(f"Looks like they have a problem: {ex}")

如何在python中禁用堆栈跟踪

2 个答案: