我的表格如下
recordId fwildcardId refNumber wildcardName wildcardValue comments
404450 154834 2 aaa p p
404450 154833 1 aa oi p
406115 154867 1 98 ff ff
406199 154869 1 aa aaaa ssss
406212 154880 1 bbbbb card comm
我需要输出
RecordId fwildcardid1 refNo1 Name1 Value1 comments1 fwildcardid2 refNo2 Name2 Value2 comments2 fwildcardid3 refNo3 Name3 Value3 comments3
404450 154834 2 aaa p p 154833 1 aa oi p
406115 Null Null Null Null Null Null Null Null Null Null 154867 1 98 ff ff
406199 Null Null Null Null Null 154869 1 aa aaaa ssss Null Null Null Null
我尝试像下面一样转动，但没有成功。
select t1.recordId,t1.wildcardid as fwildcardId,t1.refNo as refNumber,t2.wildcardName,t1.attributeValue as wildcardValue,t1.comments
into #tempp
from fwildcards t1
inner join fwildcardattributes t2 on t2.WildcardID=t1.attributenameid and t2.MarketID=5
inner join fitems t3 on t3.recordid=t1.recordid and t3.marketid=5
order by recordid,attributenameid
select * from #tempp
pivot (min (wildcardValue) for wildcardName in ([aaa],[aa],[aaaa],[98],[kki],[bbbbb],[SUN])) as wildcardValuePivot
答案 0 :(得分：1)
为了得到这个结果，你将不得不UNPIVOT和hen PIVOT数据。 UNPIVOT将采用fwildcardId，refNumber，wildcardName，wildcardValue和comments列中的值，并将其转换为行。一旦数据在行中，您就可以应用PIVOT函数来获得最终结果。
要取消数据的显示，可以使用UNPIVOT功能，也可以使用CROSS APPLY和VALUES子句。
<强> UNPIVOT ：
select recordid,
col+cast(rn as varchar(10)) col,
unpiv_value
from
(
select recordid,
cast(fwildcardid as varchar(10)) fwildcardid,
cast(refnumber as varchar(10)) refnumber,
cast(wildcardname as varchar(10)) name,
cast(wildcardvalue as varchar(10)) value,
cast(comments as varchar(10)) comments,
row_number() over(partition by recordid
order by fwildcardid) rn
from tempp
) d
unpivot
(
unpiv_value
for col in (fwildcardid, refnumber, name, value, comments)
) c
交叉申请和价值观
select recordid,
col+cast(rn as varchar(10)) col,
value
from
(
select recordid,
cast(fwildcardid as varchar(10)) fwildcardid,
cast(refnumber as varchar(10)) refnumber,
wildcardname,
wildcardvalue,
comments,
row_number() over(partition by recordid
order by fwildcardid) rn
from tempp
) d
cross apply
(
values
('fwildcardid', fwildcardid),
('refnumber', refnumber),
('name', wildcardname),
('value', wildcardvalue),
('comments', comments)
) c (col, value)
这些转换结果的格式为：
| RECORDID | COL | VALUE |
------------------------------------
| 404450 | fwildcardid1 | 154833 |
| 404450 | refnumber1 | 1 |
| 404450 | name1 | aa |
| 404450 | value1 | oi |
| 404450 | comments1 | p |
| 404450 | fwildcardid2 | 154834 |
将数据移植到同一列时，它必须是相同的数据类型。您会注意到我将cast应用于列，因此数据类型相同。
一旦数据采用行格式，您就可以使用PIVOT将其转换回列：
select *
from
(
select recordid,
col+cast(rn as varchar(10)) col,
unpiv_value
from
(
select recordid,
cast(fwildcardid as varchar(10)) fwildcardid,
cast(refnumber as varchar(10)) refnumber,
cast(wildcardname as varchar(10)) name,
cast(wildcardvalue as varchar(10)) value,
cast(comments as varchar(10)) comments,
row_number() over(partition by recordid
order by fwildcardid) rn
from tempp
) d
unpivot
(
unpiv_value
for col in (fwildcardid, refnumber, name, value, comments)
) c
) src
pivot
(
max(unpiv_value)
for col in (fwildcardid1, refnumber1, name1, value1, comments1,
fwildcardid2, refnumber2, name2, value2, comments2)
) piv;
如果你有一个已知数量的列，上面的版本效果很好，但是如果你将有一个未知数量的值转换成列，那么你需要使用动态sql来获得结果：
DECLARE @cols AS NVARCHAR(MAX),
@query AS NVARCHAR(MAX)
select @cols = STUFF((SELECT ',' + QUOTENAME(c.col+cast(rn as varchar(10)))
from
(
select row_number() over(partition by recordid
order by fwildcardid) rn
from tempp
) t
cross apply
(
select 'fwildcardid' col, 1 sortorder union all
select 'refNumber', 2 union all
select 'name', 3 union all
select 'value', 4 union all
select 'comments', 5
) c
group by col, rn, sortorder
order by rn, sortorder
FOR XML PATH(''), TYPE
).value('.', 'NVARCHAR(MAX)')
,1,1,'')
set @query = 'SELECT recordid,' + @cols + ' from
(
select recordid,
col+cast(rn as varchar(10)) col,
unpiv_value
from
(
select recordid,
cast(fwildcardid as varchar(10)) fwildcardid,
cast(refnumber as varchar(10)) refnumber,
cast(wildcardname as varchar(10)) name,
cast(wildcardvalue as varchar(10)) value,
cast(comments as varchar(10)) comments,
row_number() over(partition by recordid
order by fwildcardid) rn
from tempp
) d
unpivot
(
unpiv_value
for col in (fwildcardid, refnumber, name, value, comments)
) c
) src
pivot
(
max(unpiv_value)
for col in (' + @cols + ')
) p '
execute(@query);
见SQL Fiddle with Demo。这两个都给出了结果：
| RECORDID | FWILDCARDID1 | REFNUMBER1 | NAME1 | VALUE1 | COMMENTS1 | FWILDCARDID2 | REFNUMBER2 | NAME2 | VALUE2 | COMMENTS2 |
-------------------------------------------------------------------------------------------------------------------------------
| 404450 | 154833 | 1 | aa | oi | p | 154834 | 2 | aaa | p | p |
| 406115 | 154867 | 1 | 98 | ff | ff | (null) | (null) | (null) | (null) | (null) |
| 406199 | 154869 | 1 | kki | aaaa | ssss | (null) | (null) | (null) | (null) | (null) |
| 406212 | 154880 | 1 | bbbbb | card | comm | (null) | (null) | (null) | (null) | (null) |
答案 1 :(得分：0)
No Pivot No Cross Apply
根据编辑问题。
select
DISTINCT
A.recordId AS recordId,
A1.fwildcardId AS fwildcardId1,
A1.refNumber AS refNumber1,
A1.wildcardName AS wildcardName1,
A1.wildcardValue AS wildcardValue1,
A1.comments AS comments1,
A2.fwildcardId AS fwildcardId2,
A2.refNumber AS refNumber2,
A2.wildcardName AS wildcardName2,
A2.wildcardValue AS wildcardValue2,
A2.comments AS comments2,
A3.fwildcardId AS fwildcardId3,
A3.refNumber AS refNumber3,
A3.wildcardName AS wildcardName3,
A3.wildcardValue AS wildcardValue3,
A3.comments AS comments3,
A4.fwildcardId AS fwildcardId4,
A4.refNumber AS refNumber4,
A4.wildcardName AS wildcardName4,
A4.wildcardValue AS wildcardValue4,
A4.comments AS comments4,
A5.fwildcardId AS fwildcardId5,
A5.refNumber AS refNumber5,
A5.wildcardName AS wildcardName5,
A5.wildcardValue AS wildcardValue5,
A5.comments AS comments5,
A6.fwildcardId AS fwildcardId6,
A6.refNumber AS refNumber6,
A6.wildcardName AS wildcardName6,
A6.wildcardValue AS wildcardValue6,
A6.comments AS comments6,
A7.fwildcardId AS fwildcardId7,
A7.refNumber AS refNumber7,
A7.wildcardName AS wildcardName7,
A7.wildcardValue AS wildcardValue7,
A7.comments AS comments7,
A8.fwildcardId AS fwildcardId8,
A8.refNumber AS refNumber8,
A8.wildcardName AS wildcardName8,
A8.wildcardValue AS wildcardValue8,
A8.comments AS comments8,
A9.fwildcardId AS fwildcardId9,
A9.refNumber AS refNumber9,
A9.wildcardName AS wildcardName9,
A9.wildcardValue AS wildcardValue9,
A9.comments AS comments9,
A10.fwildcardId AS fwildcardId10,
A10.refNumber AS refNumber10,
A10.wildcardName AS wildcardName10,
A10.wildcardValue AS wildcardValue10,
A10.comments AS comments10
from Table_name A
LEFt JOIN Table_name A1 ON A.recordId=A1.recordId AND A1.wildcardName='aaa'
LEFT JOIN Table_name A2 ON A.recordId=A2.recordId AND A2.wildcardName='aa'
LEFT JOIN Table_name A3 ON A.recordId=A3.recordId AND A3.wildcardName='98'
LEFT JOIN Table_name A4 ON A.recordId=A4.recordId AND A4.wildcardName=''
LEFT JOIN Table_name A5 ON A.recordId=A5.recordId AND A5.wildcardName=''
LEFT JOIN Table_name A6 ON A.recordId=A6.recordId AND A6.wildcardName=''
LEFT JOIN Table_name A7 ON A.recordId=A7.recordId AND A7.wildcardName=''
LEFT JOIN Table_name A8 ON A.recordId=A8.recordId AND A8.wildcardName=''
LEFT JOIN Table_name A9 ON A.recordId=A9.recordId AND A9.wildcardName=''
LEFT JOIN Table_name A10 ON A.recordId=A10.recordId AND A10.wildcardName=''
<强> SQL Fiddle