java.sql.SQLException:参数索引超出范围(2>参数个数,为0)

时间:2013-04-24 15:54:53

标签: java sql exception sqlexception

public class Brothers extends javax.swing.JFrame {

    /**
     * declaring connection and SQL statement
     */

    Connection cn;
    Statement st;
    PreparedStatement pstmt=null;
    PreparedStatement pst;
    ResultSet rs;
    Object fname, mname, lname, bdate, nation, statusq,InstNo,  photo, combo, place, mimi; 
    int status;



    public Brothers() {        
        dbconnect _db = new dbconnect();

/*//////////////the above is just to show that I have two prepared statement each for each sql statement that i have //////////*/
        try {
            Class.forName("com.mysql.jdbc.Driver");
            //String unicode= "?useUnicode=yes&characterEncoding=UTF-8";
            cn = DriverManager.getConnection(_db.getHost(), _db.getUsername(), _db.getPassword());
            st=cn.createStatement(); 

 try{

        String Sql="INSERT INTO brothers(FirstName, MiddleName, LastName, BirthDate, BirthPlace, Nationality, InstituteNumber, Status, Picture) VALUES(?,?,?,?,?,?,?,?,?)";  
        pstmt=cn.prepareStatement(Sql);
        //pstmt.setString(1,txtTrial.getText());('?','?','?','?','?','?','?','?','?')
        pstmt.setString(2,txtFirtsName.getText());
        pstmt.setString(3,txtMiddleName.getText());
        pstmt.setString(4,txtLastName.getText());
        pstmt.setString(5,((JTextField)chooserBirthDate.getDateEditor().getUiComponent()).getText());
        pstmt.setString(6,txtPlacBirth.getText());

        String nations=combonation.getSelectedItem().toString();
        pstmt.setString(7,nations);
        pstmt.setString(8,txtInstituteNo.getText());


        pstmt.setObject(9,combostatus.getSelectedItem());
        pstmt.setBytes(10, person_image);

      pstmt.executeUpdate(Sql);

        JOptionPane.showMessageDialog(null, "Saving Successfull");

        }

        catch(Exception e){

          //JOptionPane.showMessageDialog(null, e);
          e.printStackTrace(); 
    }  

当我尝试使用上面的代码插入数据时,会引发异常:

java.sql.SQLException: Parameter index out of range (10 > number of parameters, which is 9).
    at com.mysql.jdbc.SQLError.createSQLException(SQLError.java:1078)
    at com.mysql.jdbc.SQLError.createSQLException(SQLError.java:989)
    at com.mysql.jdbc.SQLError.createSQLException(SQLError.java:975)
    at com.mysql.jdbc.SQLError.createSQLException(SQLError.java:920)
    at com.mysql.jdbc.PreparedStatement.checkBounds(PreparedStatement.java:3813)
    at com.mysql.jdbc.PreparedStatement.setInternal(PreparedStatement.java:3795)

我试图查看它,但我找不到问题请帮助!!

5 个答案:

答案 0 :(得分:6)

您正在第2位开始插入而不是1

 pstmt.setString(2,txtFirtsName.getText());

将其更改为

pstmt.setString(1,txtFirtsName.getText());

对最后一个

的其他人做同样的事情
pstmt.setBytes(9, person_image);

答案 1 :(得分:2)

您的SQL语句中只有9个参数。

String Sql="INSERT INTO brothers(FirstName, MiddleName, LastName, BirthDate, BirthPlace, Nationality, InstituteNumber, Status, Picture) VALUES(?,?,?,?,?,?,?,?,?)";

当您注释掉第一个setString方法调用时,您应该重新编号以下调用的参数索引。它们的编号应为1 - 9,而不是2 - 10.

答案 2 :(得分:2)

问号?的数量必须等于参数。

如果你有7个参数,那么你的陈述中应该有7个问号,即insert into table name values(?,?,?,?,?,?,?)

答案 3 :(得分:0)

第一个参数的索引应该是1而不是2,最后一个参数的索引应该是9而不是10.当分配N个参数时,索引从1变为N.

答案 4 :(得分:0)

使用 psmt.executeUpdate(); 代替 pstmt.executeUpdate(SQL);