Question

我有一个包含一系列事务对象的List。我要做的是在加载表单时在Datagridview控件中显示这些事务对象，基本上Datagridview应该表示事务寄存器的某些内容，以显示列表中每个事务对象的数据。

我必须承认在使用Datagridviews方面缺乏经验，而且我在理解我需要做什么方面遇到了一些困难。

我的问题是，如何获取列表中每个对象的详细信息以显示在Datagridview中？

这是我的代码。

首先是交易类：

public class Transaction
{
    // Class properties
    private decimal amount;
    private string type;
    private decimal balance;
    private string date;
    private string transNum;
    private string description;

    // Constructor to create transaction object with values set.
    public Transaction(decimal amount, string type, decimal currBal, string date, string num, string descrip)
    {
        this.amount = amount;
        this.type = type;
        this.balance = currBal;
        this.date = date;
        this.transNum = num;
        this.description = descrip;
    }

    // Get and Set accessors to allow manipulation of values.
    public decimal Amount
    {
        get
        {
            return amount;
        }
        set
        {
            amount = value;
        }
    }
    public string Type
    {
        get
        {
            return type;
        }
        set
        {
            type = value;
        }
    }
    public decimal Balance
    {
        get
        {
            return balance;
        }
        set
        {
            balance = value;
        }
    }
    public string Date
    {
        get
        {
            return date;
        }
        set
        {
            date = value;
        }
    }
    public string TransNum
    {
        get
        {
            return transNum;
        }
        set
        {
            transNum = value;
        }
    }
    public string Description
    {
        get
        {
            return description;
        }
        set
        {
            description = value;
        }
    }

    public decimal addCredit(decimal balance, decimal credit)
    {
        decimal newBalance;
        newBalance = balance + credit;
        return newBalance;
    }

    public decimal subtractDebit(decimal balance, decimal debit)
    {
        decimal newBalance;
        newBalance = balance - debit;
        return newBalance;
    }
    }
}

现在是“注册”表单的代码：

    public partial class Register : Form
{
    List<Transaction> tranList = new List<Transaction>();

    public Register(List<Transaction> List)
    {
        InitializeComponent();
        this.tranList = List;
    }

    private void Register_Load(object sender, System.EventArgs e)
    {
        //regView represents the Datagridview that I'm trying to work with
        regView.AutoSize = true;
        regView.DataSource = tranList;
        regView.Rows.Add(tranList[0]);
    }
}

这是我得到的输出。 Register output

Answer 1

真的有两种高级方法。

1）将手动创建的行直接添加到DataGridView。在这种情况下，您必须在更改时手动更新/删除它们。这种方法是“好的”＃34;如果您在初始化后不打算更改/更改显示内容。如果你这样做就变得站不住脚了。

要直接添加，您需要创建DataGridViewRow，并使用各个值填充它，然后将DataGridViewRow添加到DataGridView.Rows。

2）数据绑定DGV。关于数据绑定到DataGridView的文章很多。在某些情况下，将数据添加到DataTable更容易，然后从中提取DataView，并将DataGridView绑定到DataView 。其他人发现直接绑定到集合更容易。

CodeProject有一篇不错的文章让你开始走这条道路，但快速的Google搜索会产生许多其他文章。

http://www.codeproject.com/Articles/24656/A-Detailed-Data-Binding-Tutorial

Answer 2

用作DGV：

DataGridView groupListDataGridView;

柱：

DataGridViewTextBoxColumn groupListNameColumn;

列设置应如下所示：

groupListNameColumn.DataPropertyName = "name";

使用此属性，否则将添加所有列。

groupListDataGridView.AutoGenerateColumns = false;

像这样填充：

private void populateGroupList() {
    groupListDataGridView.DataSource = null;
    formattedGroupList = new SortableBindingList<DataGridGroupObject>();
    foreach (GroupObject go in StartUp.GroupList) {
        DataGridGroupObject dggo = new DataGridGroupObject();
        dggo.id = go.Id;
        dggo.name = go.Name;
        formattedGroupList.Add(dggo);
    }
    groupListDataGridView.DataSource = formattedGroupList;
    groupListDataGridView.Invalidate();
}

和型号：

public class DataGridGroupObject
{
    public int id { get; set; }      //this will be match id column
    public string name { get; set; } // this will be match name column
}

Answer 3

只需在顶部添加 using System.Linq;。然后你可以这样做：

//This will create a custom datasource for the DataGridView.
var transactionsDataSource = tranList.Select(x => new
{
        Amount = x.amount,
        Type = x.type,
        Balance = x.balance,
        Date = x.date,
        TransNum = x.transNum
        Description = x.description
}).ToList();

//This will assign the datasource. All the columns you listed will show up, and every row
//of data in the list will populate into the DataGridView.
regView.DataSource = transactionsDataSource;

使用对象列表填充datagridview

3 个答案: