Question

我的表结构如下所示：

==============================
  Id | Name | Image|
==============================

现在我想要一个带有名字的多个图像。我怎么能这样做。

if($this->request->is('post'))
        {
            if($this->Breakdown->saveAll($this->request->data['Breakdown']))
            {
            //Image insertion Successfully
            $image=$this->request->data['Breakdown'][0]['image1']['name'];
            if(!empty($this->request->data['Breakdown'][0]['image1']['name'])) 
                {
                    $image_path = $this->Image->upload_image_and_thumbnail($image,$this->data['Breakdown'][0]['image1'],600,450,180,120, "Breakdown");
                    //echo "This".$image_path;
                    if(isset($image_path)) 
                    {
                        $this->Breakdown->saveField('image',$image_path);
                        $uploaded = true;
                    }
                }
               $this->Session->setFlash('Quantity Breakdown has been added Successfully.', 'default', array('class' => 'oMsg1 oMsgError1'));
               $this->redirect('qty_breakdown');
            }
            else
            {
                 $this->set('errors', $this->Breakdown->invalidFields());   
            }

是否有其他方法可以使用循环来插入和上传多个图像？

Answer 1

我不确定我理解你在问什么，但如果你的意思是，迭代每个'Breakdown'实体，我就是这样做的：

foreach($this->request->data['Breakdown'] as $breakdown){
    //Image insertion Successfully
    $image = $breakdown['image1']['name'];
    if(!empty($breakdown['image1']['name'])){
        $image_path = $this->Image->upload_image_and_thumbnail($image,$this->data['Breakdown'][0]['image1'],600,450,180,120, "Breakdown");
            //echo "This".$image_path;
            if(isset($image_path)){
                $this->Breakdown->saveField('image', $image_path);
                $uploaded = true;
            }
        }
        $this->Session->setFlash('Quantity Breakdown has been added Successfully.', 'default', array('class' => 'oMsg1 oMsgError1'));
        $this->redirect('qty_breakdown');
}

更新时间：2013年4月29日

为了能够在视图中修改或添加多个记录，您需要以不同的方式配置视图：

// open the form
echo $this->Form->create('Breakdown');
// set the upper-bound limit of $i to whatever you like
for($i = 0; $i < 5; $i++){
    echo $this->Form->input(sprintf("Breakdown.%d.image1", $i), array('type' => 'file'));
    // add other fields using similar syntax as above:
    // Example: "Breakdown.1.name"
}
// close the form
echo $this->Form->end();

Source

多记录插入

1 个答案:

更新时间：2013年4月29日