Question

从正在从.procmailrc文件调用的python脚本进行HTTP调用时，我遇到了一个问题。你能提出一个如何解决它的方法吗？我没有选择任何选择。从命令行运行相同的脚本时，HTTP调用正常工作。以下是详细信息：

.procmailrc内容： DEFAULT = $ HOME / Maildir的/ MAILDIR = $ HOME / Maildir的 PMDIR = $ HOME / .procmail LOGFILE = / home / prasad / log.'date +％y-％m-％d' SHELL = /斌/庆典 VERBOSE = YES

:0
| /usr/bin/python /home/prasad/test.py >>/tmp/py_log.txt

从命令行运行时它可以建立网络连接。

test.py的内容：

url="http://server/book"
post_params = {
 'foo' : 'bar'
}

params = urllib.urlencode(post_params)
response = urllib2.urlopen(url, params)
print "after urlopen"
json_response = json.loads(response.read())

它挂在'response = urllib2.urlopen（url，params）'并且从未看到打印“在urlopen之后”调用。

编辑：我刚刚在procmail生成的日志文件中发现权限错误。 procmailrc在非root帐户下运行。如何解决？

procmail: Executing " /usr/bin/python /home/prasad/test.py  >>/tmp/py_log.txt"
Traceback (most recent call last):
File "/home/prasad/test.py", line 23, in <module>
  response = urllib2.urlopen(url, params)
File "/usr/lib64/python2.6/urllib2.py", line 126, in urlopen
   return _opener.open(url, data, timeout)
File "/usr/lib64/python2.6/urllib2.py", line 391, in open
   response = self._open(req, data)
File "/usr/lib64/python2.6/urllib2.py", line 409, in _open
 '_open', req)
File "/usr/lib64/python2.6/urllib2.py", line 369, in _call_chain
result = func(*args)
File "/usr/lib64/python2.6/urllib2.py", line 1190, in http_open
return self.do_open(httplib.HTTPConnection, req)
File "/usr/lib64/python2.6/urllib2.py", line 1165, in do_open
raise URLError(err)
urllib2.URLError: <urlopen error [Errno 13] Permission denied>

Python中的procmailrc和HTTP请求无法正常工作

0 个答案: