我正在使用Camel 2.10.3
这是我的骆驼背景:
<camelContext id="camelContext" xmlns="http://camel.apache.org/schema/spring">
<endpoint id="webserviceStart" uri="direct:webserviceStart"/>
<dataFormats>
<jaxb id="jaxb" prettyPrint="true"
contextPath="com.jaxbtest.package" />
</dataFormats>
<route id="myRoute">
<from ref="webserviceStart" />
<marshal ref="jaxb" />
<to uri="spring-ws:http://wshost:8010/service"/>
<unmarshal ref="jaxb" />
</route>
</camelContext>
此代码有效:
@Component
public class WebserviceClient
{
@EndpointInject( ref = "webserviceStart" )
ProducerTemplate _producer;
public Response invoke( Request input )
{
return ( Response ) _producer.sendBody( input ).getOut().getBody();
}
}
此代码(在http://camel.apache.org/pojo-producing.html之后的“使用@Produce隐藏代码中的Camel API”部分之后)不会:
@Component
public class WebserviceClient
{
public static interface MyWebservice
{
Response invoke( @Body Request body );
}
@EndpointInject( ref = "webserviceStart" )
MyWebservice _producer;
public Response invoke( Request input )
{
return ( Response ) _producer.invoke( input );
}
}
它引发了异常:
Caused by: java.io.IOException: javax.xml.bind.JAXBException: class org.apache.camel.component.bean.BeanInvocation nor any of its super class is known to this context.
at org.apache.camel.converter.jaxb.JaxbDataFormat.marshal(JaxbDataFormat.java:103)
at org.apache.camel.processor.MarshalProcessor.process(MarshalProcessor.java:59)
at org.apache.camel.util.AsyncProcessorConverterHelper$ProcessorToAsyncProcessorBridge.process(AsyncProcessorConverterHelper.java:61)
at org.apache.camel.util.AsyncProcessorHelper.process(AsyncProcessorHelper.java:73)
如果这是骆驼中的已知错误,是否有人知道与之相关的问题?我应该为此创建一个新的JIRA吗?这似乎是POJO生成的一个简单用例。
答案 0 :(得分:-2)
通常,当您收到此错误时,表示您尚未在JAXB上下文中设置类列表。
你会用JAVA DSL做的 -
JAXBContext context = JAXBContext.newInstance('your classes');
JaxbDataFormat jaxb = new JaxbDataFormat();
jaxb.setContext(context);
然后使用您的自定义数据格式'jaxb'作为您的编组/解组参考。
谢谢!