Question

用于获取非空的所有列的计数的查询;

id | Col1 | Col2 | Col3 | Col4 |
--------------------------------
1  | abc  | ---  |  xyz | pqr  |
--------------------------------
2  | def  |  ghi |  --- | pqr  |
--------------------------------
3  | ---  |  --- | hgy  | ---  |
--------------------------------
4  | ---  | jko  |      | uyi  |
--------------------------------

SELECT COUNT(*) FROM table 1 WHERE Col1!='---'

SELECT COUNT(*) FROM table 1 WHERE Col2!='---'

SELECT COUNT(*) FROM table 1 WHERE Col3!='---'

在单个查询中

如何获得结果

-----------------------
Cnt1| Cnt2 |Cnt3| Cnt4|
-----------------------
2   |  2   | 2  |  3  |
-----------------------

Answer 1

有趣的是：

select count(col1) cnt1, count(col2) cnt2, count(col3) cnt3, count(col4) cnt4
from table1

Answer 2

试试这个：

with data as (
  select * 
  from ( values
      (null, null, null, null),
      (   1, null, null, null),
      (   2,    4, null, null),
      (   0,    5,    6, null)
  ) data(col1,col2,col3,col4)
) 
select 
  sum(case when col1 is null then 0 else 1 end),
  sum(case when col2 is null then 0 else 1 end),
  sum(case when col3 is null then 0 else 1 end),  
  sum(case when col4 is null then 0 else 1 end)
from data

很好地产生：

 ----------- ----------- ----------- -----------  
          3           2           1           0

Answer 3

看起来你有“---”值而不是空值。在这种情况下：

select count(nullif(col1,'---')) as cnt1, count(nullif(col2,'---')) as cnt2, count(nullif(col1,'---')) as cnt3, count(nullif(col1,'---')) as cnt4 from table1;

所有非空列的计数

3 个答案: