Question

我正在尝试建立一家银行，我正在制作一个扫描仪选项，所以如果你按1你可以提取钱，如果你按2你将加钱和3下车。但是当我按下2或3时它没有做任何事情，我尝试了其他但是然后我得到了更多错误，我不知道其中的区别。

------ ------注我尝试了un nesting（如果那是一个短语）但是我在按钮附近的其他地方得到了语法错误（我已标记在哪里）所以我不知道如何解决这个问题

import java.util.Scanner;




public class Bank {




    public static void main (String [] args) {
     System.out.println("Welcome To Harry's Bank");


    //Pin System
        System.out.println("Please Enter Your Bank Pin.");
    Scanner userInput = new Scanner (System.in);
        int number;
        int password = 7123;
        int amount = 4000;

        number = userInput.nextInt();

        if (number == password) {
        System.out.println("Pin Accepted");
        System.out.println("You Have Now Entered Harry's Bank!");
        System.out.println("Press The Number Of The Option You Would Like.");
        System.out.println("1.Withdraw Money.");
        System.out.println("2.Put In Money");
        System.out.println("3.Exit Bank");
        Scanner Options = new Scanner (System.in);
        int option;
        option = userInput.nextInt();

        if (option == 1) {
        //Withdraw Money System
        System.out.println("You Have £4000");
        System.out.println("How Much Would You Like To Take Out?");
        Scanner Input = new Scanner (System.in);
        int numbere;


        numbere = userInput.nextInt();
        if (numbere < 4000) {

        int money = amount - numbere;
            System.out.println("You Have Now £" + money);
            System.out.println("Thank You For Banking At Harry's Bank!");
            System.out.println("Please Come Again!");
          }else{
                System.out.println("You Do Not Have Enough Money!"); 
          }
        }


        else if (option == 2) {
            //AddMoney System
            Scanner AddMoney = new Scanner (System.in);
            int AddMoney1;
            AddMoney1 = userInput.nextInt();
            int NewMoney = (amount + AddMoney1);
            System.out.println("How Much Would You Like To Enter?");
            System.out.println("You Now Have " + NewMoney + "!");
            System.out.println("Thank You For Using Harry's Bank!");




        }
        else if (option == 3) {
            System.out.println("");
            System.out.println("");
            System.out.println("");
            System.out.println("");
            System.out.println("");
            System.out.println("");
            System.out.println("");
            System.out.println("Goodbye!");
        }
        }else{
            System.out.println("Next Time Only Press 1,2 or 3!");
        }
         //error Here For Else "Syntax error on token "else", { expected"
        }else{
                System.out.println("Pin Declined!");

          }



            }








        }

Answer 1

您的括号已关闭。

if(option ==1)
{
     if(option == 2)
     {
         //stuff
     }

     if(option == 3)
     {
         //stuff
     }
}

将那些ifs移出第一个

Answer 2

因为第3和第4 if语句不可及。如果你不按1，它们将永远不会被触及。

Answer 3

您的if语句嵌套在if for“option == 1”中，因此您无法访问选项2或3，如果是

，这应该是其他链接

为什么我的变量不起作用？

3 个答案: