我有一个关于wait()和notifyAll()方法的问题。 代码模拟两个线程的'Race'。
让我们看一下代码 - 问题是notifyAll()方法对等待线程什么都不做,导致main方法首先获得锁定...简单的解决方法是设置一些延迟(参见注释行)。但这是一种不好的做法。这个问题的好方法是什么?我希望只使用wait / notifyAll / join方法。public class TestThreads {
public static void main(String[] args) throws InterruptedException {
System.out.println("_start main");
Object lock = new Object();
Thread t1 = new Thread(new Car("Red car", lock));
Thread t2 = new Thread(new Car("Black car", lock));
t1.start();
t2.start();
//Thread.sleep(10L);
synchronized (lock){
System.out.println("Let`s go!");
lock.notifyAll();
}
t1.join();
t2.join();
System.out.println("_exiting from main...");
}
}
class Car implements Runnable {
private final String name;
private final Object lock;
public Car(String name, Object lock) {
this.name = name;
this.lock = lock;
}
@Override
public void run() {
int distance = 100;
synchronized (lock){
try{
System.out.println(name + " waiting...");
lock.wait();
}catch (InterruptedException e){
e.printStackTrace();
}
}
System.out.println(name + " started...");
while (distance != 0){
try{
Thread.sleep((long) (100 * Math.random()));
}catch (InterruptedException e){
e.printStackTrace();
break;
}
distance--;
if (distance % 20 == 0 && distance != 0){
System.out.println(name + " " + distance+ " miles left");
}
else if (distance == 0){
System.out.println(name + " finished race!!!");
}
}
System.out.println("_exiting from thread of " + name + " move simulation...");
}
}
PS。抱歉我的英语不好。
谢谢你的回答。 那么,这个解决方案更好吗?
public class TestThreads {
public static void main(String[] args) throws InterruptedException {
System.out.println("_start main");
LightSignal lock = new LightSignal();
Thread t1 = new Thread(new Car("Red car", lock));
Thread t2 = new Thread(new Car("Black car", lock));
t1.start();
t2.start();
synchronized (lock){
Thread.sleep(1000L);
lock.isGreen = true;
System.out.println("Let`s go!");
lock.notifyAll();
}
t1.join();
t2.join();
System.out.println("_exiting from main...");
}
}
class Car implements Runnable {
private final String name;
private final LightSignal lock;
public Car(String name, LightSignal lock) {
this.name = name;
this.lock = lock;
}
@Override
public void run() {
int distance = 100;
synchronized (lock){
try{
while (!lock.isGreen){
System.out.println(name + " waiting...");
lock.wait();
}
}catch (InterruptedException e){
e.printStackTrace();
}
}
System.out.println(name + " started...");
while (distance != 0){
try{
Thread.sleep((long) (100 * Math.random()));
}catch (InterruptedException e){
e.printStackTrace();
break;
}
distance--;
if (distance % 20 == 0 && distance != 0){
System.out.println(name + " " + distance + " miles left");
}
}
System.out.println(name + " finished race!!!");
System.out.println("_exiting from thread of " + name + " move simulation...");
}
}
class LightSignal {
public boolean isGreen = false;
}
答案 0 :(得分:1)
当您调用notifyAll()时,您需要更改状态,当您等待()时,您需要在循环中检查该状态。如果你不这样做
在这种情况下,最简单的解决方案是不用担心。你正在等待一个长达100毫秒的随机延迟,所以尝试同步这样一个随机系统的开始是不太可能的。
当循环退出时,我认为“竞赛已完成”,您不需要if
子句。