如何避免在团队成员中重新输入相同的功能?

时间:2013-05-09 01:54:20

标签: javascript

如何避免在团队成员中重新输入相同的功能?团队obj中的所有成员都可以使用say_name函数。如何编写我的代码?

<script type="text/javascript">
var team={
  // member
  jimmy:{
    name:'jimmy',
    say_name:function (){}
  },
  darcy:{
    name:'darcy',
    say_name:function(){}
  },
  // common functions
  say_name: function(){
    // every member has the say_name function, I don't want to write the same code in each member. How to do?
    alert('my name is ??')
  }
}
</script>

3 个答案:

答案 0 :(得分:2)

使用bind

var say_name = function () {
    alert("my name is " + this.name);
}

var jimmy = {
    name: 'jimmy',
    say_name: say_name.bind(jimmy)
};

jimmy.say_name(); // my name is jimmy

虽然可能有更简单明了的方法。

答案 1 :(得分:1)

你可以使用原型,首先定义一个construtcor函数:

function Team(){

}

Team.prototype.say_name=function(){
     // every team will have this method
}

建立一个团队:

var team=new Team();//now the team has a method called say_name
team.jimmy={name:'jimmy'}
更新


这里有一篇关于javascript常用模式的精彩文章,非常值得一读:) http://addyosmani.com/resources/essentialjsdesignpatterns/book/

答案 2 :(得分:1)

制定这个答案花了一点时间。我想你想拥有多个具有变量名称等的多重播放器实例的团队实例。如果是这种情况,那么硬编码一个吉米成员就不是可行的了。

// object defenition
function Team(){
  // property unuque for every team so teamB and teamC
  // would not have the same members
  this.members=[];
}
// properties shared by all team instances so teamB and teamC 
//   would refer to the same function
Team.prototype.addMember=function(name){
  this.members.push(new TeamMember(name));
}
Team.prototype.getMember=function(name){
  for(var i=0;i<this.members.length;i++){
    if(this.members[i].name===name){
      return this.members[i];
    }
  }
}


// Define a TeamMember, this is the definition, Bob would be
//   and instance o TeamMember; like var Bob=new TeamMember("Bob");
function TeamMember(name){
  this.name=name;
}
// properties shared by all TeamMember instance objects
//   so bill and jane will point to this function
TeamMember.prototype.sayName=function(){
  console.log("My name is:" + this.name);
}
// end of object definition

//creating instances
var teamB=new Team();
var teamC=new Team();
teamB.addMember("Tom");
teamB.addMember("Harry");
teamC.addMember("July");
teamC.addMember("Mary");
teamC.getMember("July").sayName();
相关问题