Question

我发现了一个可能是个错误的神秘问题！我的片段中有一个列表。每行都有一个按钮。列表不应响应单击，但按钮是可单击的。

为了获得点击的按钮，我创建了一个监听器并在我的片段中实现它。这是我的适配器的代码。

public class AddFriendsAdapter extends BaseAdapter {

    public interface OnAddFriendsListener {
        public void OnAddUserClicked(MutualFriends user);
    }

    private final String TAG = "*** AddFriendsAdapter ***";

    private Context context;
    private OnAddFriendsListener listener;
    private LayoutInflater myInflater;
    private ImageDownloader imageDownloader;
    private List<MutualFriends> userList;

    public AddFriendsAdapter(Context context) {
        this.context = context;
        myInflater = LayoutInflater.from(context);

        imageDownloader = ImageDownloader.getInstance(context);
    }

    public void setData(List<MutualFriends> userList) {
        this.userList = userList;

        Log.i(TAG, "List passed to the adapter.");
    }

    @Override
    public int getCount() {
        try {
            return userList.size();
        } catch (Exception e) {
            e.printStackTrace();
            return 0;
        }
    }

    @Override
    public Object getItem(int position) {
        return null;
    }

    @Override
    public long getItemId(int position) {
        return position;
    }

    @Override
    public View getView(final int position, View convertView, ViewGroup parent) {
        ViewHolder holder;

        if (convertView == null) {
            convertView = myInflater.inflate(R.layout.list_add_friends_row, null);
            holder = new ViewHolder();

            Typeface font = Typeface.createFromAsset(context.getAssets(), "fonts/ITCAvantGardeStd-Demi.ttf");
            holder.tvUserName = (TextView) convertView.findViewById(R.id.tvUserName);
            holder.tvUserName.setTypeface(font);
            holder.ivPicture = (ImageView) convertView.findViewById(R.id.ivPicture);
            holder.btnAdd = (Button) convertView.findViewById(R.id.btnAdd);
            holder.btnAdd.setOnClickListener(new View.OnClickListener() {
                @Override
                public void onClick(View v) {
                    Log.e(TAG, "Item: " + position);
                    listener.OnAddUserClicked(userList.get(position));
                }
            });

            convertView.setTag(holder);
        } else {
            holder = (ViewHolder) convertView.getTag();
        }

        holder.tvUserName.setText(userList.get(position).getName());
        imageDownloader.displayImage(holder.ivPicture, userList.get(position).getPhotoUrl());

        return convertView;
    }

    public void setOnAddClickedListener(OnAddFriendsListener listener) {
        this.listener = listener;
    }

    static class ViewHolder {
        TextView tvUserName;
        ImageView ivPicture;
        Button btnAdd;
    }
}

当我运行应用程序时，我可以看到我的行但是因为我的列表很长并且有200多个项目当我转到列表中间并单击一个项目然后返回的位置是错误的（它有点像7，有时是4等等））。

现在神秘是什么？如果我从我的片段激活列表的项目监听器并单击行，那么如果我点击该按钮则会显示正确的行位置，然后将显示错误的位置。

listView.setOnItemClickListener(new AdapterView.OnItemClickListener() {
            @Override
            public void onItemClick(AdapterView<?> parent, View view, int position, long id) {
                Log.e(TAG, "item " + position + " clicked.");
            }
        });

导致logcat：

05-09 10:22:25.228: E/AddFriendsFragment(20296): item 109 clicked.
05-09 10:22:34.453: E/*** AddFriendsAdapter ***(20296): Item: 0

任何建议都将不胜感激。感谢

Answer 1

由于convertView和持有人将被回收使用，请将您的setOnClickListener移出if else语句：

    if (convertView == null) {
        convertView = myInflater.inflate(R.layout.list_add_friends_row, null);
        holder = new ViewHolder();

        Typeface font = Typeface.createFromAsset(context.getAssets(), "fonts/ITCAvantGardeStd-Demi.ttf");
        holder.tvUserName = (TextView) convertView.findViewById(R.id.tvUserName);
        holder.tvUserName.setTypeface(font);
        holder.ivPicture = (ImageView) convertView.findViewById(R.id.ivPicture);
        holder.btnAdd = (Button) convertView.findViewById(R.id.btnAdd);
        convertView.setTag(holder);
    } else {
        holder = (ViewHolder) convertView.getTag();
    }
    holder.btnAdd.setOnClickListener(new View.OnClickListener() {
         @Override
         public void onClick(View v) 
                Log.e(TAG, "Item: " + position);
                listener.OnAddUserClicked(userList.get(position));
            }
        });

这不是最好的解决方案，因为会有一些性能问题。我建议您为视图创建一个Map，并为您的项目创建一个新视图，然后只使用每个视图的相对视图。

我认为这将是一个更好的解决方案，具有最佳性能：

@Override
public View getView(final int position, View convertView, ViewGroup parent) {
    ViewHolder holder;

    if (convertView == null) {
        convertView = myInflater.inflate(R.layout.list_add_friends_row, null);
        holder = new ViewHolder();

        Typeface font = Typeface.createFromAsset(context.getAssets(), "fonts/ITCAvantGardeStd-Demi.ttf");
        holder.tvUserName = (TextView) convertView.findViewById(R.id.tvUserName);
        holder.tvUserName.setTypeface(font);
        holder.ivPicture = (ImageView) convertView.findViewById(R.id.ivPicture);
        holder.btnAdd = (Button) convertView.findViewById(R.id.btnAdd);
        holder.btnAdd.setOnClickListener(new View.OnClickListener() {
            @Override
            public void onClick(View v) {
                Integer pos = (Integer)v.getTag();
                Log.e(TAG, "Item: " + pos);
                listener.OnAddUserClicked(userList.get(pos));
            }
        });

        convertView.setTag(holder);
    } else {
        holder = (ViewHolder) convertView.getTag();
    }

    holder.tvUserName.setText(userList.get(position).getName());
    imageDownloader.displayImage(holder.ivPicture, userList.get(position).getPhotoUrl());
    holder.btnAdd.setTag(position);
    return convertView;
}

您也可以自己管理视图。为项目创建每个唯一视图，不要回收视图。

//member various
private Map<Integer, View> myViews = new HashMap<Integer, View>(); 

@Override
public View getView(final int position, View convertView, ViewGroup parent) {
    ViewHolder holder;
    View view = myViews.get(position);
    if (view == null) {
        view = myInflater.inflate(R.layout.list_add_friends_row, null);
        //don't need use the holder anymore.

        Typeface font = Typeface.createFromAsset(context.getAssets(), "fonts/ITCAvantGardeStd-Demi.ttf");
        holder.tvUserName = (TextView) convertView.findViewById(R.id.tvUserName);
        holder.tvUserName.setTypeface(font);
        holder.ivPicture = (ImageView) convertView.findViewById(R.id.ivPicture);
        holder.btnAdd = (Button) convertView.findViewById(R.id.btnAdd);
        holder.btnAdd.setOnClickListener(new View.OnClickListener() {
            @Override
            public void onClick(View v) {
                Integer pos = (Integer)v.getTag();
                Log.e(TAG, "Item: " + pos);
                listener.OnAddUserClicked(userList.get(pos));
            }
        });

       holder.tvUserName.setText(userList.get(position).getName());
       imageDownloader.displayImage(holder.ivPicture,  
                userList.get(position).getPhotoUrl());
       myViews.put(position, view);

    }
    return view;
}

Answer 2

你有没有试过这样的事情：

holder.btnAdd.setTag(Integer.valueOf(position));

然后检索在按钮的回调中单击了哪一行，如下所示：

public void btnAddClickListener(View view)
    {
        position = (Integer)view.getTag();
        Foo foo = (Foo)foos_adapter.getItem(position);  //get data of row(position)
        //do some
    }

Answer 3

我发现另一种有用的方法（如果你当然使用ViewHolder模式）是在调用getView（）时在单独的属性上设置索引，然后在你的onClickListener中你只需要引用你的holder的位置属性，像这样：

@Override
public View getView(int position, View convertView, ViewGroup parent) {

    final ViewHolder holder;

    if(convertView == null){

        convertView = View.inflate(mContext, R.layout.contact_picker_row,null);

        holder = new ViewHolder();

        holder.body = (RelativeLayout)convertView.findViewById(R.id.numberBody);

        convertView.setTag(holder);

    }else{

        holder = (ViewHolder)convertView.getTag();

    }

    holder.position = position;

    holder.body.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View v) {

            Toast.makeText(mContext,"Clicked on: "+holder.position,Toast.LENGTH_LONG).show();

        }
    });

    return convertView;
}

private class ViewHolder{

    RelativeLayout body;
    int position;

}

Android，List Adapter在getView中返回错误的位置

3 个答案: