Question

我试着编写一个bash脚本来读取每个进程的cpu使用情况。但是，我认为我做错了。当我测试这个脚本时，它给了我一个不正确的百分比。继承人代码：

prev_total=0
prev_idle=0
prev_processtotal=0
prev_utime=0
while true; do
cpu=`cat /proc/stat | head -n1 | sed 's/cpu  //'`
user=`echo $cpu | awk '{print $1}'`
system=`echo $cpu | awk '{print $2}'`
nice=`echo $cpu | awk '{print $3}'`
idle=`echo $cpu | awk '{print $4}'`
wait=`echo $cpu | awk '{print $5}'`
irq=`echo $cpu | awk '{print $6}'`
srq=`echo $cpu | awk '{print $7}'`
zero=`echo $cpu | awk '{print $8}'`
total=$(($user+$system+$nice+$idle+$wait+$irq+$srq+$zero))
diff_idle=$(($idle-$prev_idle))
diff_total=$(($total-$prev_total))
usage=$(($((1000*$(($diff_total-$diff_idle))/$diff_total+5))/10))
process=`cat /proc/20966/stat`
utime=`echo $process | awk '{print $14}'`
stime=`echo $process | awk '{print $15}'`
cutime=`echo $process | awk '{print $16}'`
cstime=`echo $process | awk '{print $17}'`
processtotal=$(($utime+$stime+$cutime+$cstime))
diff_processtotal=$(($processtotal-$prev_processtotal))
diff_utime=$(($utime-$prev_utime))
processusage=$(($((1000*$(($diff_processtotal-$diff_utime))/$diff_processtotal+5))/10))
clear
echo "total cpu usage: $usage%"
echo "one selected process: $processusage%"
prev_total=$total
prev_idle=$idle
prev_processtotal=$processtotal
prev_utime=$utime
sleep 1
done

我有点迷失在这里，所以任何帮助都会非常感激：）

Answer 1

prev_total=0
prev_idle=0
prev_processtotal=0
prev_utime=0
while true; do
cpu=`cat /proc/stat | head -n1 | sed 's/cpu  //'`
user=`echo $cpu | awk '{print $1}'`
system=`echo $cpu | awk '{print $2}'`
nice=`echo $cpu | awk '{print $3}'`
idle=`echo $cpu | awk '{print $4}'`
wait=`echo $cpu | awk '{print $5}'`
irq=`echo $cpu | awk '{print $6}'`
srq=`echo $cpu | awk '{print $7}'`
zero=`echo $cpu | awk '{print $8}'`
total=$(($user+$system+$nice+$idle+$wait+$irq+$srq+$zero))
diff_idle=$(($idle-$prev_idle))
diff_total=$(($total-$prev_total))
usage=$(($((1000*$(($diff_total-$diff_idle))/$diff_total+5))/10))
process=`cat /proc/19240/stat`
utime=`echo $process | awk '{print $14}'`
stime=`echo $process | awk '{print $15}'`
cutime=`echo $process | awk '{print $16}'`
cstime=`echo $process | awk '{print $17}'`
processtotal=$(($utime+$stime+$cutime+$cstime))
diff_processtotal=$(($processtotal-$prev_processtotal))
diff_utime=$(($utime-$prev_utime))
processusage=$(($((1000*$(($diff_processtotal***4**))/$diff_total+5))/10))
clear
echo "total cpu usage: $usage%"
echo "one selected process: $processusage%"
prev_total=$total
prev_idle=$idle
prev_processtotal=$processtotal
prev_utime=$utime
sleep 1
done

我有一个四核，结果我不得不将该值乘以4 ... 现在问题解决了;）

使用bash脚本的每个进程的cpu使用率

1 个答案: