我正在尝试在我的xml文件中获取子节点并将其打印出来......但是我不能。它只是打印一个元素而不是全部。请帮忙。
XDocument doc = XDocument.Load(GlobalClass.GlobalUrl);
XElement xelement = XElement.Load(GlobalClass.GlobalUrl);
var query = from nm in xelement.Elements("EmployeeFinance")
where (int)nm.Element("EmpPersonal_Id") == empID
select new AllowancePaid
{
Income_ID = (decimal)nm.Element("Allowance-Grade")
.Element("Amount")
};
var x = query.ToList();
foreach (var ele in x) {
Debug.WriteLine(ele.Income_ID);
}
我的XML文件
<EmployeeFinance>
<EmployeeEmploy_Id>4891</EmployeeEmploy_Id>
<EmpPersonal_Id>28407</EmpPersonal_Id>
<Employee_Number>11715</Employee_Number>
<Allowance-Grade>
<Amount BenListID="32">6000.00</Amount>
<Amount BenListID="59">100000.00</Amount>
</Allowance-Grade>
</EmployeeFinance>
添加元素
var result = from element in doc.Descendants("EmployeeFinance")
where int.Parse(element.Element("EmpPersonal_Id").Value) == tt.Employee_Personal_InfoEmp_id
select element;
foreach (var ele in result)
{
ele.Element("Allowance-Grade")
.Add(new XElement("Amount", new XAttribute("BenListID", tt.ID), tt.Amount));
doc.Save(GlobalClass.GlobalUrl);
}
答案 0 :(得分:2)
问题是您选择了一个量节点.Element("Amount")
但是节点很多。将其更改为.Elements("Amount")
,需要更改一些地方。我没有测试,但逻辑应该像下面的东西一样
`
var query = from nm in xelement.Elements("EmployeeFinance")
where (int)nm.Element("EmpPersonal_Id") == empID
select new AllowancePaid
{
AllowanceList = nm.Element("Allowance-Grade").Elements("Amount").Select( a=>(decimal)a.Value).ToList()
};
foreach (var ele in query) {
foreach (var a in ele.AllowanceList) {
Debug.WriteLine(a);
}
}
答案 1 :(得分:0)
XDocument xelement = XDocument.Parse(xml);
var query = from nm in xelement.Elements("EmployeeFinance")
where (int)nm.Element("EmpPersonal_Id") == 28407
select new
{
Amounts = nm.Element("Allowance-Grade")
.Elements("Amount")
.Select(
row =>
new {
id = row.Value
}
).ToList()
};
var x = query.ToList();
foreach (var ele in x)
{
foreach(var a in ele.Amounts)
Console.WriteLine(a);
}