我是初学python程序员，我正在尝试制作俄罗斯方块游戏。当我运行游戏时，块每秒向下移动10个像素。问题是随机块只是停止，打印语句我也停止打印。根据任务经理的说法，我没有收到任何错误，内存也没问题。我有一个celeron处理器32位Vista，但我也尝试在带有i5处理器的Windows 7上运行，问题仍然存在，所以我迷路了。
这是代码：
import pygame
from pygame.locals import *
from datetime import datetime
import Blocks
def Gravity(Box, rate):
# Gravity effect
Box.set_yCoor(Box.get_yCoor()+ rate)
Box.Edge.set_yCoor(Box.Edge.get_yCoor()+ rate)
return Box
def main():
# initailize all pygame modules
pygame.init()
windowWidth,windowHeight= 640,700
screen_color= (255,255,255)
# Determines how many pixels per time the box will fall
gravity= 10
# Create screen/window and change color to white
screen= pygame.display.set_mode((windowWidth,windowHeight),0,32)
screen.fill(screen_color)
# Used to determine whether to draw box and apply gravity
index =0
# Put box and border info in list
# Args: (x,y) (len, width) (color)
boxInfo= [10,10, 20,50, (0,0,0)]
borderInfo= [5,5, 30,60, (154,24,214)]
# Create instance of box and pass info
Box= Blocks.Box(boxInfo, borderInfo)
#Create an endless loop that the game will run inside of
while True:
for event in pygame.event.get():
if event.type== QUIT:
pygame.quit()
return
# Get second and millisecond time and convert to string
startTime= str(datetime.now())
# Splice time string and convert to float
startTime= float(startTime[17:23])
if index== 0:
# Pull the box down by gravity
Box= Gravity(Box, gravity)
# Move box back to the top of window
if Box.Edge.get_yCoor() > windowHeight - Box.Edge.get_boxWid():
Box.Edge.set_yCoor(5)
Box.set_yCoor(10)
# Clear screen
screen.fill(screen_color)
# Display Screen
Box.display(screen)
# Set the stop time used to determine when to call gravity and display
stopTime= startTime+ 1
index= 1
# Get second and millisecond time and convert to string
bug= str(datetime.now())
# Splice time string and convert to float
bug= bug[17:23]
print("\nDisplayed at:")
print('Start:', startTime)
print('Stop:', stopTime)
print('Bug:', bug)
elif startTime >= stopTime:
index= 0
# Get second and millisecond time and convert to string
bug= str(datetime.now())
# Splice time string and convert to float
bug= bug[17:26]
print("\nNot displaying at:")
print('Start:', startTime)
print('Stop:', stopTime)
print('Bug:', bug)
# Call main
main()
这是块类： 导入pygame 来自pygame.locals import *
class Box():
def __init__(self, boxInfo, edgeInfo):
# Pixel location of the box
self.__xCoor= boxInfo[0]
self.__yCoor= boxInfo[1]
# Pixel length and width of the box
self.__boxLen= boxInfo[2]
self.__boxWid= boxInfo[3]
# Pixel color is white by default
self.__color= boxInfo[4]
self.Edge= Border(edgeInfo)
# ---- ACCESSORS -- and -- MUTATORS ----
def set_xCoor(self,Coordx):
self.__xCoor= Coordx
def get_xCoor(self):
return self.__xCoor
def set_yCoor(self,Coordy):
self.__yCoor= Coordy
def get_yCoor(self):
return self.__yCoor
def set_boxLen(self,Length):
self.__boxLen= Length
def get_boxLen(self):
return self.__boxLen
def set_boxWid(self,Width):
self.__boxWid= Width
def get_boxWid(self):
return self.__boxWid
def set_color(self,color):
self.__color= color
def get_color(self):
return self.__color
# ---- METHODS ----
def boxStatCheck(self):
# Prints all the attributes in the shell for debug
print("x-Coordinate=", self.get_xCoor())
print("y-Coordinate=", self.get_yCoor())
print("Box Length=", self.get_boxLen())
print("Box Width=", self.get_boxWid())
print("Color Value=", self.get_color())
def display(self, screen):
screen.lock()
pygame.draw.rect(screen, self.Edge.get_color(), Rect((self.Edge.get_xCoor(),self.Edge.get_yCoor()),
(self.Edge.get_boxLen(),self.Edge.get_boxWid())))
pygame.draw.rect(screen, self.get_color(), Rect((self.get_xCoor(),self.get_yCoor()),
(self.get_boxLen(),self.get_boxWid())))
screen.unlock()
pygame.display.update()
class Border():
def __init__(self, listInfo):
# Pixel location of the box
self.__xCoor= listInfo[0]
self.__yCoor= listInfo[1]
# Pixel length and width of the box
self.__boxLen= listInfo[2]
self.__boxWid= listInfo[3]
# Pixel color is white by default
self.__color= listInfo[4]
# ---- ACCESSORS -- and -- MUTATORS ----
def set_xCoor(self,Coordx):
self.__xCoor= Coordx
def get_xCoor(self):
return self.__xCoor
def set_yCoor(self,Coordy):
self.__yCoor= Coordy
def get_yCoor(self):
return self.__yCoor
def set_boxLen(self,Length):
self.__boxLen= Length
def get_boxLen(self):
return self.__boxLen
def set_boxWid(self,Width):
self.__boxWid= Width
def get_boxWid(self):
return self.__boxWid
def set_color(self,color):
self.__color= color
def get_color(self):
return self.__color
# ---- METHODS ----
def boxStatCheck(self):
# Prints all the attributes in the shell for debug
print("x-Coordinate=", self.get_xCoor())
print("y-Coordinate=", self.get_yCoor())
print("Box Length=", self.get_boxLen())
print("Box Width=", self.get_boxWid())
print("Color Value=", self.get_color())
def display(self, screen):
pygame.draw.rect(screen, self.get_color(), Rect((self.get_xCoor(),self.get_yCoor()),
(self.get_boxLen(),self.get_boxWid())))
答案 0 :(得分：2)
我认为您的问题在于如何使用datetime来控制何时移动块。
你应该看看pygame.time模块。我建议你创建一个变量（例如wanted_fps），其中包含一个整数，表示你希望无限循环每秒运行一次。 您的代码应该如下所示：
wanted_fps = 1 # how often I want the endless loop to run per second
fpsHandler = pygame.time.Clock() # fpsHandler created to handle fps
while(True): # our endless loop
# do something awesome
fpsHandler.tick(wanted_fps) # makes sure fps isn't higher than wanted_fps
你可以在这里阅读pygame.time： http://www.pygame.org/docs/ref/time.html
此外，如果你想要一个看似没有事件处理延迟的东西，你可以将wanted_fps设置为60之类，然后制作某种计数器变量（例如mycounter）来处理你想要发生什么事情的频率。让我们说你在无限循环中做了类似的事情：
# handle events
if mycounter > 0:
mycounter -= 1
else:
# do something amazing
mycounter = 30
你做的事情每秒60/30 = 2次，但你每秒处理事件60次，因此你可以立即回应事件。
答案 1 :(得分：0)
因为您通过向startTime添加1来设置stopTime，所以当startTime变为59.xx时，stopTime将变为大于60的值。然后startTime返回0，因为它是一个新的分钟而且您被卡住了。 index = 1并且startTime永远不会大于stopTime。 if或elif语句都不会评估为True。如果您的目标是在再次绘制框之前加入延迟，请考虑做这样的事情......
pauseLength = 120
然后在游戏循环中......
pygame.time.delay(pauseLength)
这也可以让你以后加快游戏速度。