我有两种几乎相同的方法。唯一的区别是方法签名。最后一个参数可以是一个对象,也可以是一个对象列表。我觉得有一种方法可以将这些结合起来,但我不知道如何。
public Query where(String selection, String operator, Object value) {
WhereClause clause = null;
try {
if (!columns.contains(selection)) {
throw new Exception("No such field for the " + model.getClass().getSimpleName() + " model: " + selection);
}
clause = new WhereClause(selection, operator, value);
} catch (Exception e) {
clause = null;
e.printStackTrace();
}
if (clause != null) {
clauses.add(clause);
}
return this;
}
public Query where(String selection, String operator, List<Object> values) {
WhereClause clause = null;
try {
if (!columns.contains(selection)) {
throw new Exception("No such field for the " + model.getClass().getSimpleName() + " model: " + selection);
}
clause = new WhereClause(selection, operator, values);
} catch (Exception e) {
clause = null;
e.printStackTrace();
}
if (clause != null) {
clauses.add(clause);
}
return this;
}
答案 0 :(得分:2)
public Query where(String selection, String operator, Object value)
{
ArrayList<Object> list = new ArrayList<Object>();
list.add( value );
return where(selection, operator, list);
}
编辑:
如果你错过了Eric的评论,你也可以使用:
List<Object> list = Collections.singletonList(value)
return where(selection, operator, list);
答案 1 :(得分:1)
您可以将第一个方法的最后一个参数包装在单个列表中(如Eric Jablow所建议的那样),让方法2完成所有工作:
public Query where(String selection, String operator, Object value)
{
List<Object> v = Collections.singletonList(value);
return where(selection, operator, v);
}