我正在使用python 2.6 当前输出
mylist = [('log:A', '1009.2'), ('log:B', '938.1'), ('log:C', '925.7'), ('log:C', '925.7')]
我正在尝试添加值以产生以下内容: 排名从高到低。 我遇到的问题是将log:C标签加在一起。 而不是输出两次。
log:C = 1851.4
log:A = 1009.2
log:B = 938.1
答案 0 :(得分:3)
使用collections.defaultdict
:
>>> strs = "log:A 22 log:B 44 log:C 74 log:D 24 log:B 10"
>>> from collections import defaultdict
>>> dic = defaultdict(int)
>>> it = iter(strs.split())
>>> for k in it:
... dic[k] += int(next(it))
...
>>> for k,v in sorted(dic.items(), key = lambda x: x[1], reverse = True):
... print k,v
...
log:C 74
log:B 54
log:D 24
log:A 22
根据值获取项目的排序列表:
>>> sorted(dic.items(), key = lambda x: x[1], reverse = True)
[('log:C', 74), ('log:B', 54), ('log:D', 24), ('log:A', 22)]
更新:根据您的新输入
>>> mylist = [('log:A', '1009.2'), ('log:B', '938.1'), ('log:C', '925.7'), ('log:C', '925.7')]
>>> dic = defaultdict(int)
>>> for k,v in mylist:
dic[k] += float(v)
...
>>> sorted(dic.items(), key = lambda x: x[1], reverse = True)
[('log:C', 1851.4), ('log:A', 1009.2), ('log:B', 938.1)]
答案 1 :(得分:2)
mystr = 'log:A 22 log:B 44 log:C 74 log:D 24 log:B 10'
li=mystr.split()
res={}
for k,v in zip(li[::2],li[1::2]):
res.setdefault(k,[]).append(int(v))
print res
打印:
{'log:D': [24], 'log:A': [22], 'log:C': [74], 'log:B': [44, 10]}
然后总结一下:
for k in sorted(res):
print k, sum(res[k])
打印:
log:A 22
log:B 54
log:C 74
log:D 24
答案 2 :(得分:0)
import collections
import operator
mystr = "log:A 22 log:B 44 log:C 74 log:D 24 log:B 10"
s = mystr.split()
d = collections.defaultdict(int)
for i in xrange(0, len(s), 2):
d[s[i]] += int(s[i+1])
# alternate way:
# i = iter(s)
# for k, v in itertools.izip(i, i):
# d[k] += int(v)
result = sorted(d.iteritems(), key=operator.itemgetter(1), reverse=True)
# [('log:C', 74), ('log:B', 54), ('log:D', 24), ('log:A', 22)]