如何在MYSQL tempTable结果中将行显示为列

Question

Net，MYSQL Web应用程序。 我们创建了将返回表的存储过程，但是现在为了显示目的想改变那个程序的结构。 那么如何使Mysql存储过程的TempTable结果采用以下格式？ 行转换为列。

Phoenix Solution输出：

Answer 1

试试这个sql

select max((CASE WHEN Agedreceivable='Current' then AgedeceivableAmt ELSE 0 END)) as Current,
max((CASE WHEN Agedreceivable='1-30' then AgedeceivableAmt ELSE 0 END)) as '1-30',
max((CASE WHEN Agedreceivable='31-60' then AgedeceivableAmt ELSE 0 END)) as '31-60',
max((CASE WHEN Agedreceivable='61-90' then AgedeceivableAmt ELSE 0 END)) as '61-90',
max((CASE WHEN Agedreceivable='>90' then AgedeceivableAmt ELSE 0 END)) as '>90'
from yourtable;

由于你没有提到你的entite表细节，我建议将这些记录分组到一些适当的字段，你将获得所需的输出，否则你可以关注@ peterm的解决方案。

示例小提琴FIDDLE

Answer 2

尝试

SELECT 
       SUM(CASE WHEN Agedreceivable='Current' THEN AgedreceivableAmt END) Current,
       SUM(CASE WHEN Agedreceivable='1-30' THEN AgedreceivableAmt END) '1-30',
       SUM(CASE WHEN Agedreceivable='31-60' THEN AgedreceivableAmt END) '31-60',
       SUM(CASE WHEN Agedreceivable='61-90' THEN AgedreceivableAmt END) '61-90',
       SUM(CASE WHEN Agedreceivable='>90' THEN AgedreceivableAmt END) '>90'
  FROM
(
  SELECT @n := @n + 1 rownum, agedreceivable, agedreceivableamt
    FROM temp, (SELECT @n := 0) z
) y
 GROUP BY FLOOR((rownum - 1) / 5)

输出：

| CURRENT | 1-30 | 31-60 | 61-90 | >90 |
----------------------------------------
|       0 |    0 |     0 |     0 |   0 |
|   12993 |    0 |     0 |     0 |   0 |

这是 SQLFiddle 演示