Question

如何避免从输出中显示前导./

实际输出

test@testmachine:/usr/lib$ find . -name "*" -exec echo {} \;
.
./pymodules/python2.7/pyliblzma-0.5.3.egg-info
./pymodules/python2.7/pyliblzma-0.5.3.egg-info/PKG-INFO
./pymodules/python2.7/pyliblzma-0.5.3.egg-info/top_level.txt
./pymodules/python2.7/pyliblzma-0.5.3.egg-info/dependency_links.txt
./pymodules/python2.7/pyliblzma-0.5.3.egg-info/SOURCES.txt

必填项：

test@testmachine:/usr/lib$ find . -name "*" -exec xxxxxxxxxx \;

pymodules/python2.7/pyliblzma-0.5.3.egg-info
pymodules/python2.7/pyliblzma-0.5.3.egg-info/PKG-INFO
pymodules/python2.7/pyliblzma-0.5.3.egg-info/top_level.txt
pymodules/python2.7/pyliblzma-0.5.3.egg-info/dependency_links.txt
pymodules/python2.7/pyliblzma-0.5.3.egg-info/SOURCES.txt

Answer 1

不要将.指定为搜索目录。

find * -exec echo {} \;

命令的-name '*'部分不会删除以.开头的名称，但是通常会删除名称。如果这是一个问题，请在.[!.]*之前添加-exec（跳过.和..，还要..hidden;您决定是否重要）。< / p>

使用exec echo选项查找命令包含./ in filename

1 个答案: