Question

我现在正在使用注册表单，该表单允许为个人资料图片上传照片。尝试提交时，除了图片索引给出的错误外，所有内容都能成功运行。

我非常相信它与在表单中运行php有关，因为在提交之前图片没有上传到变量但是我无法通过它。

注意：未定义的索引：第54行/var/www/registeraccount.php中的照片

注意：未定义的索引：第57行/var/www/registeraccount.php中的照片

<?php
error_reporting(E_ALL);
ini_set('display_errors',"On");
include ('database_connection.php');
$target = "/var/www/profile";

if (isset($_POST['formsubmitted'])) {
    $error = array();//Declare An Array to store any error message  
    if (empty($_POST['name'])) {//if no name has been supplied 
        $error[] = 'Please Enter a name ';//add to array "error"
    } else {
        $name = $_POST['name'];//else assign it a variable
    }

    if (empty($_POST['e-mail'])) {
        $error[] = 'Please Enter your Email ';
    } else {


        if (preg_match("/^([a-zA-Z0-9])+([a-zA-Z0-9\._-])*@([a-zA-Z0-9_-])+([a-zA-Z0-9\._-]+)+$/", $_POST['e-mail'])) {
           //regular expression for email validation
            $Email = $_POST['e-mail'];
        } else {
             $error[] = 'Your EMail Address is invalid  ';
        }


    }


    if (empty($_POST['Password'])) {
        $error[] = 'Please Enter Your Password ';
    } else {
        $Password = $_POST['Password'];
    }


    if (empty($error)) //send to Database if there's no error '

    { // If everything's OK...

        // Make sure the email address is available:
        $query_verify_email = "SELECT * FROM account  WHERE email ='$Email'";
        $result_verify_email = mysqli_query($dbc, $query_verify_email);
        if (!$result_verify_email) {//if the Query Failed ,similar to if($result_verify_email==false)
            echo ' Database Error Occured ';
        }

        if (mysqli_num_rows($result_verify_email) == 0) { // IF no previous user is using this email .


            // Create a unique  activation code:
            $activation = md5(uniqid(rand(), true));
            $target = $target . basename($_FILES['photo']['name']);

//This gets all the other information from the form
            $pic=($_FILES['photo']['name']);



            $query_insert_user = "INSERT INTO `account` ( `username`, `passwords`, `email`, `picture`) VALUES ( '$name', '$Password', '$Email ' , '$pic')";


            $result_insert_user = mysqli_query($dbc, $query_insert_user);
            if (!$result_insert_user) {
                echo 'Query Failed ';
            }

            if (mysqli_affected_rows($dbc) == 1) { //If the Insert Query was successfull.


                // Send the email:
                $message = " To activate your account, please click on this link:\n\n";
                $message .= WEBSITE_URL . '/activate.php?email=' . urlencode($Email) . "&key=$activation";
                mail($Email, 'Registration Confirmation', $message, 'From: systemadminstrator@theanimator.com');

                // Flush the buffered output.


                // Finish the page:
                echo '<div class="success">Thank you for
registering! A confirmation email
has been sent to '.$Email.' Please click on the Activation Link to Activate your account </div>';


            } else { // If it did not run OK.
                echo '<div class="errormsgbox">You could not be registered due to a system
error. We apologize for any
inconvenience.</div>';
            }

        } else { // The email address is not available.
            echo '<div class="errormsgbox" >That email
address has already been registered.
</div>';
        }

    } else {//If the "error" array contains error msg , display them



echo '<div class="errormsgbox"> <ol>';
        foreach ($error as $key => $values) {

            echo '  <li>'.$values.'</li>';



        }
        echo '</ol></div>';

    }

    mysqli_close($dbc);//Close the DB Connection

} // End of the main Submit conditional.



?><!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Registration Form</title>





<style type="text/css">
//CSS Once again removed because it has nothing to do with the issue.
</style>

</head>
<body>


<form action="registeraccount.php" method="post" class="registration_form" enctype="multipart/form-data">
  <fieldset>
    <legend>Registration Form </legend>

    <h2 style="text-align:center">Create an account!</h2>
    <p style="text-align:center"> <span>Already a member? <a href="login.php">Log in</a></span> </p>

    <div class="elements">
      <label for="name">Name :</label>
      <input type="text" id="name" name="name" size="25" />
    </div>
    <div class="elements">
      <label for="e-mail">E-mail :</label>
      <input type="text" id="e-mail" name="e-mail" size="25" />
    </div>
    <div class="elements">
      <label for="Password">Password:</label>
      <input type="password" id="Password" name="Password" size="25" />
      <p>
              Photo:
            </p>
            <input type="hidden" name="size" value="350000">
            <input type="file" name="photo"> 
            <p>
      </div>

      <br />

    <div class="submit">
     <input type="hidden" name="formsubmitted" value="TRUE" />
      <input type="submit" value="Register" />

    </div>
  </fieldset>
</form>
<button onclick="window.location='theanimator.html';">Go Back!</button>
</body>
</html>

Answer 1

添加条件以检查照片是否已上传是一件简单的事情

if(!isset($_FILES['photo'])) {
    $error[] = "No photo selected !";
}

照片上传PHP未定义索引。将照片插入sql数据库

1 个答案: