int N = 2345;
var digitArray = N.ToString().ToCharArray();
int multiplicationSum = 1;
foreach (char digit in digitArray)
{
multiplicationSum = int.Parse(digit.ToString()) * multiplicationSum;
}
var sum = 0;
var sumArray = multiplicationSum.ToString().ToCharArray();
foreach (char digit in sumArray)
{
sum = int.Parse(digit.ToString()) + sum;
}
由于
答案 0 :(得分:7)
假设您不需要处理负数,那么在数学上做这样做会更有意义
int N = 2345;
int multiplicationSum = 1;
while(N!=0)
{
multiplicationSum = multiplicationSum * (N%10);
N = N/10;
}
var sum = 0;
while(multiplicationSum!=0)
{
sum = sum + (multiplicationSum%10);
multiplicationSum = multiplicationSum/10;
}
参考文献:
%运算符在将第一个操作数除以第二个操作数后计算余数
分割两个整数时,结果始终为整数。例如,7/3的结果是2