Question

我想在Oracle（10g）中获得详细的查询计划和实际执行，类似于PostgreSQL中的EXPLAIN ANALYZE。有没有等价的？

Answer 1

最简单的方法是在sql * plus中使用autotrace。

SQL> set autotrace on exp
SQL> select count(*) from users ;

  COUNT(*)
----------
    137553


Execution Plan
----------------------------------------------------------
   0      SELECT STATEMENT Optimizer=ALL_ROWS (Cost=66 Card=1)
   1    0   SORT (AGGREGATE)
   2    1     INDEX (FAST FULL SCAN) OF 'SYS_C0062362' (INDEX (UNIQUE)
          ) (Cost=66 Card=137553)

或者，oracle确实有一个explain plan语句，您可以执行该查询，然后查询各种计划表。最简单的方法是使用DBMS_XPLAN包：

SQL> explain plan for select count(*) from users ;

Explained.
SQL> SELECT * FROM table(DBMS_XPLAN.DISPLAY);

--------------------------------------------------------------
| Id  | Operation             | Name         | Rows  | Cost  |
--------------------------------------------------------------
|   0 | SELECT STATEMENT      |              |     1 |    66 |
|   1 |  SORT AGGREGATE       |              |     1 |       |
|   2 |   INDEX FAST FULL SCAN| SYS_C0062362 |   137K|    66 |
--------------------------------------------------------------

如果你是老派，你可以自己查询计划表：

SQL> explain plan set statement_id = 'my_statement' for select count(*) from users;

Explained.

SQL> column "query plan" format a50
SQL> column object_name format a25
SQL> select lpad(' ',2*(level-1))||operation||' '||options "query plan", object_name
from plan_table
start with id=0 and statement_id = '&statement_id'
connect by prior id=parent_id 
  and prior statement_id=statement_id
Enter value for statement_id: my_statement
old   3: start with id=0 and statement_id = '&statement_id'
new   3: start with id=0 and statement_id = 'my_statement'

SELECT STATEMENT
  SORT AGGREGATE
    INDEX FAST FULL SCAN                           SYS_C0062362

Oracle过去常常附带一个实用程序文件utlxpls.sql，该文件具有该查询的更完整版本。在$ORACLE_HOME/rdbms/admin下查看。

对于上述任何一种方法，您的DBA必须已经设置了相应的计划表。

Oracle相当于Postgres EXPLAIN ANALYZE

1 个答案: