Question

我正在阅读以下格式的文件：

0.012281001     00:1c:c4:c2:1f:fe       1    30
0.012285001     00:1c:c4:c2:1f:fe       3    40
0.012288001     00:1c:c4:c2:1f:fe       2    50
0.012292001     00:1c:c4:c2:1f:fe       4    60
0.012295001     24:1c:c4:c2:2f:ce       5    70

我打算将第2列实体作为键，将第3列和第4列作为单独的值。对于我遇到的每一行，对于该特定键，它们各自的值必须相加（值1和值2应分别为该键聚合）。在上面提到的例子中，我需要得到如下输出：

'00:1c:c4:c2:1f:fe': 10 : 180, '24:1c:c4:c2:2f:ce': 5 : 70

我为简单的1键1值编写的程序如下：

#!/usr/bin/python

import collections
result = collections.defaultdict(int)
clienthash = dict()

with open("luawrite", "r") as f:
    for line in f:
            hashes = line.split()
            ckey = hashes[1]
            val1 = float(hashes[2])
            result[ckey] += val1
    print result

如何将此值扩展为2个值，如何将其打印为上述输出。我没有得到任何想法。请帮忙！顺便说一下，我正在使用python2.6

Answer 1

您可以使用元组作为存储值将所有值存储在单个字典中：

with open("luawrite", "r") as f:
    for line in f:
        hashes = line.split()
        ckey = hashes[1]
        val1 = int(hashes[2])
        val2 = int(hashes[3])
        a,b = result[ckey] 
        result[ckey] = (a+val1, b+val2) 
print result

同时在字典中操作键的两个值

1 个答案: