我想用黑白alpha蒙版掩盖一个Bitmap。我的蒙版图像是黑白的,黑色区域表示透明,白色区域表示OPAQUE。
我需要的是: 当我使用此蒙版图像来遮盖任何其他图像时,如果蒙版图像的相应区域是黑色,则所得图像的区域应该是透明的。否则,结果图像的区域应该是OPAQUE。
我附上了样本图片。请帮帮我这个家伙。
到目前为止我尝试了什么: 以下方法工作正常。但它们很慢。我需要一些比速度和内存更有效的解决方案。
第一种方法:
int width = rgbDrawable.getWidth();
int height = rgbDrawable.getHeight();
if (width != alphaDrawable.getWidth() || height != alphaDrawable.getHeight()) {
throw new IllegalStateException("image size mismatch!");
}
Bitmap destBitmap = Bitmap.createBitmap(width, height,
Bitmap.Config.ARGB_8888);
int[] pixels = new int[width];
int[] alpha = new int[width];
for (int y = 0; y < height; y++)
{
rgbDrawable.getPixels(pixels, 0, width, 0, y, width, 1);
alphaDrawable.getPixels(alpha, 0, width, 0, y, width, 1);
for (int x = 0; x < width; x++)
{
// Replace the alpha channel with the r value from the bitmap.
pixels[x] = (pixels[x] & 0x00FFFFFF) | ((alpha[x] << 8) & 0xFF000000);
}
destBitmap.setPixels(pixels, 0, width, 0, y, width, 1);
}
alphaDrawable.recycle();
rgbDrawable.recycle();
return destBitmap;
第二种方法
float[] nlf = new float[] {
0, 0, 0, 0, 0,
0, 0, 0, 0, 0,
0, 0, 0, 0, 0,
1, 0, 0, 0, 0};
ColorMatrix sRedToAlphaMatrix = new ColorMatrix(nlf);
ColorMatrixColorFilter sRedToAlphaFilter = new ColorMatrixColorFilter(sRedToAlphaMatrix);
// Load RGB data
Bitmap rgb = rgbDrawable;
// Prepare result Bitmap
Bitmap target = Bitmap.createBitmap(rgb.getWidth(), rgb.getHeight(), Bitmap.Config.ARGB_8888);
Canvas c = new Canvas(target);
c.setDensity(Bitmap.DENSITY_NONE);
// Draw RGB data on our result bitmap
c.drawBitmap(rgb, 0, 0, null);
// At this point, we don't need rgb data any more: discard!
rgb.recycle();
rgb = null;
// Load Alpha data
Bitmap alpha = alphaDrawable;
// Draw alpha data on our result bitmap
final Paint grayToAlpha = new Paint();
grayToAlpha.setColorFilter(sRedToAlphaFilter);
grayToAlpha.setXfermode(new PorterDuffXfermode(PorterDuff.Mode.DST_IN));
c.drawBitmap(alpha, 0, 0, grayToAlpha);
// Don't need alpha data any more: discard!
alpha.recycle();
alpha = null;
return target;