我已经给了它一些尝试,而我可以创建代码,使我能够使它适用于诸如“查找”或“其他”之类的单词我无法使其适用于以两个开头的单词或更多辅音。我的具体问题是有没有办法让程序搜索a,i,o,u或e中的一个?所以我可以使用IndexOf + Substring来请求它们使用的第一个实例的位置来完成这个问题。
到目前为止,我的代码是: -
Private Sub btnCompute_Click(sender As System.Object, e As System.EventArgs) Handles btnCompute.Click
Dim word As String = CStr(txtInput.Text)
Dim first_letter As String = word.Substring(0, 1)
Const vovel As String = "aeiouy"
Const constants As String = "bcdfjklmnopqrstvwxz"
Dim find As String = word.Substring(0, vovel)
Dim delete As String = word.Substring(vovel, constants)
If vovel.Contains(first_letter) Then
txtResults.Text = txtInput.Text & "way"
ElseIf constants.Contains(first_letter) Then
txtResults.Text = delete & find & "ay"
End If
End Sub
结束班
非常感谢任何帮助或建议
答案 0 :(得分:2)
您可以使用正则表达式,例如[aeiou]
。
然后使用Index
属性在匹配
答案 1 :(得分:1)
如果我理解了这个问题,你可以使用; e.g
char[] vowels = new char[] { 'a', 'e', 'i', 'o', 'u' };
string word = "test";
var index = word.IndexOfAny(vowels);
答案 2 :(得分:0)
对于你想要做的事,这是一种方式:
Private Function IgpayAtinlay(word As String) As String
Dim vowels As String = "aeiou"
Dim Upper As Boolean = False
If Char.IsUpper(word(0)) Then Upper = True
For I = 0 To word.Length - 1
If vowels.Contains(word(I)) Then
If I = 0 Then
'If the vowel is the first letter add "way" to the end
word = word + "way"
Exit For
Else
'Otherwise we take the rest of the word starting at the vowel,
'put the beginning letters on the end and add "ay"
word = word.ToLower
word = word.Substring(I) + word.Substring(0, I) + "ay"
'If the first letter was upper case then make the new first letter
'the same
If Upper Then word = word(0).ToString.ToUpper + word.Substring(1)
Exit For
End If
End If
Next
Return word
End Function
Private Sub btnCompute_Click(sender As System.Object, e As System.EventArgs) Handles btnCompute.Click
txtResults.Text = IgpayAtinlay(txtInput.Text)
End Sub
我提供了代码来维护第一个字母的情况
TODO:
使用单词列表验证输入,以确保它是有效的单词。