UITableView从不调用didSelectRowAtIndexPath

时间:2013-06-25 14:48:47

标签: ios uitableview nsurlconnection

我正在使用UITableView进行Json解析。

 -(void) connectionDidFinishLoading :(NSURLConnection *) connection{

     self.resultTable.delegate = self;

     self.resultTable.dataSource = self; }

我正在解析数据并设置UITableView's delegatedatasource个自我。

当我编译该程序时,我使用jSON解析的数据正确无误地运行。

主要问题是:当我尝试点击行表时,调试器永远不会来

- (void)tableView:(UITableView *)tableView didSelectRowAtIndexPath:(NSIndexPath *)indexPath 

我尝试过很多东西(包括segue等......)但是我不能用手指轻敲任何单元格的行。这真的让我感觉像是在点击文本字段......

有人知道这个问题吗?

最诚挚的问候......

- 编辑 -

-(UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath
{
    _userSettings = [NSUserDefaults standardUserDefaults];

    static NSString *CellIdentifier =@"CellID";


    ResultNearbyList *cell= [tableView dequeueReusableCellWithIdentifier:CellIdentifier];

    [cell.profilePictureIndicator startAnimating];

        if (cell == nil) {
            cell = [[ResultNearbyList alloc] initWithStyle:UITableViewCellStyleSubtitle reuseIdentifier:CellIdentifier];
        }

        cell.userProfilePicture.profileID = [userFBIDArray objectAtIndex:indexPath.row];

    self.userDOBStr = [userDOB objectAtIndex:indexPath.row];

    self.userGenderStr = [userGender objectAtIndex:indexPath.row];

        [cell.profilePictureIndicator stopAnimating];

        [_listNearbyView stopAnimating];


        cell.userNickName.text = [userNickNameArray objectAtIndex:indexPath.row];

        NSString *fullName = [userFullNameArray objectAtIndex:indexPath.row];


        NSString* fullNameUTF8 = [NSString stringWithUTF8String:[fullName cStringUsingEncoding:NSUTF8StringEncoding]];


        //NSString *fullNameUTF8 = [NSString stringWithCString:[fullName cStringUsingEncoding:NSISOLatin1StringEncoding] encoding:NSUTF8StringEncoding];


        cell.userFullName.text = fullNameUTF8;

        NSString *userCityCountry = [userCountryArray objectAtIndex:indexPath.row];

        userCityCountry = [userCityCountry stringByAppendingString:@"/"];

        userCityCountry = [userCityCountry stringByAppendingString:[userCityArray objectAtIndex:indexPath.row]];

        cell.userCityCountry.text = userCityCountry;

        NSString *userDestination = [userDistanceArray objectAtIndex:indexPath.row];

        NSRange range = [userDestination rangeOfString:@"."];

        NSString *substring = (range.location != NSNotFound) ? [userDestination substringToIndex:range.location] : nil;

        substring = [substring stringByAppendingString:@" km"];

        if([substring intValue] == 0)
        {
            substring = (range.location != NSNotFound) ? [userDestination substringFromIndex:range.location] : nil;

            substring = [substring substringWithRange:NSMakeRange(0, 4)];

            substring = [substring stringByAppendingString:@" m"];
        }



        cell.userDistance.text = substring;

        return cell; 

}

屏幕截图:1

2 个答案:

答案 0 :(得分:0)

转到故事板,选择UITable并检查选择是否设置为“单选”。另请注意复选标记“显示触摸选择”

enter image description here

答案 1 :(得分:0)

我发现了自己的错误。我缺少的部分是,我只是将Objective-c类文件添加为UIViewController,用于创建Cell原型视图。比我改变了UIViewController - > UITableViewCell中。但是手动更改为类类型,没有添加以下实例:

- (id)initWithStyle:(UITableViewCellStyle)style reuseIdentifier:(NSString *)reuseIdentifier
{
    self = [super initWithStyle:style reuseIdentifier:reuseIdentifier];
    if (self) {
        // Initialization code
    }
    return self;
}

- (void)setSelected:(BOOL)selected animated:(BOOL)animated
{
    [super setSelected:selected animated:animated];

    // Configure the view for the selected state
}

当我将这些实例设置为我的UItableViewCell类实现文件时,问题已修复:)

感谢您的帮助......

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