Question

NSString *login = @"Web Guest";
NSString *password = @"xxxxx";
NSError *myError = nil;

NSLog(@"CONNECTION: Adding credentials");

NSURLCredential *credential = [NSURLCredential credentialWithUser:login
                                                         password:password
                                                      persistence:NSURLCredentialPersistenceForSession];

NSURLProtectionSpace *protectionSpace = [[NSURLProtectionSpace alloc]
                                         initWithHost:@"54.225.xxx.xxx"
                                         port:80
                                         protocol:@"http"
                                         realm:@"54.225.xxx.xxx" 
                                         authenticationMethod:NSURLAuthenticationMethodDefault];

//Not sure if set up correctly

[[NSURLCredentialStorage sharedCredentialStorage] setDefaultCredential:credential forProtectionSpace:protectionSpace];   

NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:[NSURL URLWithString:@"xx.xxx.xxx.xxx/blah"]
                                                       cachePolicy:NSURLRequestReloadIgnoringCacheData
                                                   timeoutInterval:12];

NSLog(@"CONNECTION: Running request");

//Perform the request
NSURLResponse *response;

NSData *data = [NSURLConnection
                sendSynchronousRequest:request
                returningResponse:&response
                error:&myError];

此时，我收到错误“由于未捕获而终止应用异常'NSInvalidArgumentException'，原因：'+ [NSString stringWithCString：encoding：]：NULL cString'“

NSString *result = [NSString stringWithCString:[data bytes] encoding:NSUTF8StringEncoding];

NSLog(@"Webserver response: %@", result);

我正在尝试从Web服务器返回一些JSON，这需要使用基本身份验证进行授权，但似乎在设置它时遇到了一些麻烦。我是Objective-c编程和ios开发的新手，但非常感谢任何帮助！感谢。

Answer 1

您未在请求网址字符串中使用方案：@＆＃34; xx.xxx.xxx.xxx/blah"。你需要像@＆＃34; https://xx.xxx.xxx.xxx/blah＆＃34;这样的东西，否则[NSURL URLWithString：]会返回nil。

带/凭证的NSURLRequest for JSON

1 个答案: