Question

我有3个表，A, B和C，列

UserId, CompanyId, Quantity, Rate

我想查询返回结果，如下面的查询

SELECT 
    (A.Quantity + B.Quantity + C.Quantity) AS TotalQuantity, 
    SUM(A.Quantity * A.Rate) + SUM(C.Quantity * C.Rate) AS TotalAmount, 
    TotalQuantity/TotalAmount AS Result 
FROM 
    A, B, C  
WHERE
    (A.UserId = 1 AND A.CompanyId = 1) 
    AND 
    (A.UserId = B.UserId AND A.UserId = C.UserId AND A.CompanyId = B.CompanyId 
     AND A.CompanyId = C.CpmpanyId)

我尝试过运行此查询，但它的工作方式不符合预期。我在这里遗漏了一些东西。请帮助我。

Table A 

UID    CID    Quantity  Rate
1       1      90        60
1       1      100        9


Table B

UID    CID    Quantity
1       1       100
1       1       50

Table C

UID    CID    Quantity  Rate
1       1       5        5
1       1       5        5

Answer 1

根据编辑过的问题更改查询：

select sum(Quantity) TotalQuantity, sum(Quantity * Rate) TotalAmount, sum(Quantity) / sum(Quantity * Rate * 1.0) Result
from
(
   select UID, CID, Quantity, Rate
   from A
   union all
   select UID, CID, Quantity, 1 Rate
   from B
   union all
   select UID, CID, Quantity, Rate
   from C
) t
where
   t.UID = 1 
   and t.CID = 1

此处还有working example

Answer 2

数据的问题在于连接会复制行。 A.UID = B.UID AND A.CID = B.CID将每一行链接两次。

尝试使用以下联合

SELECT SUM(t.TotalQuantity), SUM(t.TotalAmount), SUM(t.TotalQuantity)/SUM(t.TotalAmount) FROM (
    SELECT 
        CID, UID, SUM(Quantity) AS TotalQuantity, SUM(Quantity*Rate) AS TotalAmount
    FROM A 
    GROUP BY CID, UID
    UNION ALL
    SELECT 
        CID, UID, SUM(Quantity), 0
    FROM B 
    GROUP BY CID, UID
    UNION ALL
    SELECT 
        CID, UID, SUM(Quantity), SUM(Quantity*Rate)
    FROM C 
    GROUP BY CID, UID
) t
WHERE t.UID=1 AND t.CID=1

要按照评论中的要求按公司分组数据：

SELECT t.CID, SUM(t.TotalQuantity), SUM(t.TotalAmount), SUM(t.TotalQuantity)/SUM(t.TotalAmount) FROM (
    SELECT 
        CID, UID, SUM(Quantity) AS TotalQuantity, SUM(Quantity*Rate) AS TotalAmount
    FROM A 
    GROUP BY CID, UID
    UNION ALL
    SELECT 
        CID, UID, SUM(Quantity), 0
    FROM B 
    GROUP BY CID, UID
    UNION ALL
    SELECT 
        CID, UID, SUM(Quantity), SUM(Quantity*Rate)
    FROM C 
    GROUP BY CID, UID
) t
WHERE t.UID=1
GROUP BY t.CID

在SQL Server中选择连接多个表的查询

2 个答案: