如何将php curl_setopt翻译成ruby等价物?

时间:2013-07-02 09:31:36

标签: php ruby curl translate

我需要一些帮助将php脚本翻译成ruby

php脚本:

$apiUrl = 'http://someurl/' . $_POST['type'];
unset($_POST['type']);

$fields = $_POST;
$fields['ip'] = $_SERVER['REMOTE_ADDR'];
$fieldsString = http_build_query($fields);

$ch = curl_init();

////set the url, number of POST vars, POST data
curl_setopt($ch,CURLOPT_HEADER, true);
curl_setopt($ch, CURLOPT_HTTPHEADER, array(
'Api-Key: somekey'
));
curl_setopt($ch,CURLOPT_URL, $apiUrl);
curl_setopt($ch,CURLOPT_POST, count($fieldsString));
curl_setopt($ch,CURLOPT_POSTFIELDS, $fieldsString);
echo "<pre>";
var_dump($fields);
////execute post
$result = curl_exec($ch);
////close connection
curl_close($ch);
exit;

到目前为止我做过的红宝石代码..

postparams = {
    'sent_from'         => 2,
    'id'                => @client.id,
    ...etc...
    'type'              => type,
    'ip'                => request.remote_ip
}

apiUrl = "http://someurl/#{type}"
fields = postparams

#$fieldsString = http_build_query($fields);
fieldsString = fields.to_query

#$ch = curl_init();
easy = Curl::Easy.new
#curl_setopt($ch,CURLOPT_HEADER, true);

# curl_setopt($ch, CURLOPT_HTTPHEADER, array(
#     'Api-Key: somekey'
# ));
easy.headers = ["Api-Key: somekey"]
#curl_setopt($ch,CURLOPT_URL, $apiUrl);
easy.url     = apiUrl
#curl_setopt($ch,CURLOPT_POST, count($fieldsString));

#curl_setopt($ch,CURLOPT_POSTFIELDS, $fieldsString);
res = easy.http_post(apiUrl, fieldsString)

#$result = curl_exec($ch);

render :text => res.inspect

所以问题是:

  • 我如何翻译#curl_setopt($ ch,CURLOPT_POST,count($ fieldsString));
  • 我如何翻译#curl_setopt($ ch,CURLOPT_HEADER,true);
  • 会easy.http_post执行我打算做什么吗?那是用给定的标题按钮等发布参数...
  • 任何其他建议

谢谢

1 个答案:

答案 0 :(得分:1)

  

如何翻译#curl_setopt($ ch,CURLOPT_HEADER,true);

像这样:

 easy.header_in_body = true
  

我如何翻译#curl_setopt($ ch,CURLOPT_POST,   计数($ fieldsString));

php curl_setopt()文档说:

  

CURLOPT_HTTPGET TRUE

     

将HTTP请求方法重置为GET。由于 GET是默认,   只有在请求方法发生变化时才需要这样做。

换句话说,如果你写:

curl_setopt($ch,CURLOPT_POST, FALSE);

请求默认为get请求。所以......

http_method = (postparams.length==0) ? 'get' : 'post'
easy.http(http_method)
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