Question

这个问题对我的需求非常具体，因此我找不到最佳方法。

我想要做的是从表格name中抓取surname和people，然后将它们合并到一个数组中，最终得到这样的结果：

"Bob Jones","Tony Wright", ..等等。

我正在使用PDO。这就是我所拥有的：

$attrs = array(PDO::ATTR_PERSISTENT => true);

// connect to PDO
$pdo = new PDO("mysql:host=localhost;dbname=new", "root", "root", $attrs);

// the following tells PDO we want it to throw Exceptions for every error.
// this is far more useful than the default mode of throwing php errors
$pdo->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);

$conn = $pdo->prepare("SELECT name, surname FROM people");

$conn->execute();
$results = $conn->fetchAll();

foreach($results as $row){

    $fullName = $row['name'] . "," . $row['surname'];

    print_r($fullName);
}

我已经尝试过一些东西，我只是暂时坚持使用这段代码。任何帮助或建议都非常感谢。

Answer 1

$arr = array();
foreach($results as $row) {
   $arr[] = "{$row['name']},{$row['surname']}";
}
echo implode($arr);

Answer 2

您也可以在SQL中解决此问题，因此不再需要foreach。

只需替换

SELECT name, surname FROM people

与

SELECT CONCAT_WS(' ', name, surname) FROM people

Answer 3

从数据库中获取行后，需要循环结果集并将组合名称分配给新数组：

<?php

// result set from database
$results = $conn->fetchAll();

// create an empty array to store our names
$names = array();

// loop over result set and add entry to $names array
foreach ($results as $result) {
    $names[] = $row['name'] . ' ' . $row['surname'];
}

print_r($names);

Answer 4

$fullname =array();
foreach($results as $row){
        $fullName = $row['name'] . " " . $row['surname'];
}
print_r($fullname);

如何从MySQL获取和组合数据，然后在PHP中插入到数组中

4 个答案: