GAE servlet的doPost()不起作用

时间:2013-07-07 22:16:51

标签: java google-app-engine jsp servlets

我在JSP中遇到了问题,我有以下servlet:

@SuppressWarnings("serial")
public class HelloAppIgorServlet extends HttpServlet {
    public void doGet(HttpServletRequest req, HttpServletResponse resp) throws IOException, ServletException {
        RequestDispatcher disp = req.getRequestDispatcher("/mainpage.jsp");
        disp.forward(req, resp);
    }

    @Override
    protected void doPost(HttpServletRequest req, HttpServletResponse resp) throws ServletException, IOException {
        PrintWriter pw = resp.getWriter();
        pw.print("Test");
        pw.close();
    }
}

和一个名为mainpage.jsp的JSP文件:

<%@ page language="java" contentType="text/html; charset=ISO-8859-1"
    pageEncoding="ISO-8859-1"%>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1">
<title>Insert title here</title>
</head>
<body>
    <p>Hello there!<p>
    <form action="." method="post">
        <input type="text" name="name1" />
        <input type="submit" value="name2" />
    </form>
</body>
</html>

问题是doPost()方法不起作用。当我点击按钮时,它会将我重定向到index.html页面。我确定问题不在servlet中,所以它可以在哪里?

1 个答案:

答案 0 :(得分:1)

您需要在<form action="." method="post">中设置相应的操作。该操作是您在<servlet-mapping>中通过web.xml定义的servlet的(相对)URL。