Question

我尝试使用运行时命令从我的代码运行一个jar。jar通过RMI连接到另一个主机。它通过异常并退出。

但是当我从cmd打开jar时，它运行正常。

jar有5个参数。

代码：

String runCommand = "java -jar WhiteboardStudent.jar "
        + "192.168.0.3" + " " 
        + "2000" + " " 
        + "2001" + " " 
        + "test" + " 0" ;
final Process proc = Runtime
        .getRuntime()
        .exec(runCommand,null,new File("util/"));

命令提示符：

 java -jar WhiteboardStudent.jar 192.168.0.3 2000 2001 test 0

抛出异常的代码在这里：

 Object proxy = registry.lookup("RWD");
 Whiteboard whiteboard = (Whiteboard)proxy;

我只是难倒。有什么想法？

抛出异常的函数：

Registry registry = LocateRegistry.getRegistry(
                hostname, Integer.parseInt(whiteboardPort)
                );
String serviceName = "RemoteWhiteboard" + sessionID;
Object proxy = registry.lookup(serviceName);
Whiteboard whiteboard = (Whiteboard)proxy;
int userid = whiteboard.userRegistry(userName, "");
Main mainFrame = new Main(sessions, sessionID,
    whiteboard,userid,"");

Answer 1

我的建议是尝试代码中的绝对路径：

String runCommand = "java -jar /c/users/xxx/WhiteboardStudent.jar "
    + "192.168.0.3" + " " 
    + "2000" + " " 
    + "2001" + " " 
    + "test" + " 0" ;

是运行时.getRuntime（）。exec（）环境与cmd环境不同吗？

1 个答案: