Question

我有两个文件 - 在C：\ Test中的abc.txt和abx.xls。我正在检查如何在Java中使用类似glob的语法，并遇到below代码：

/**
 * Sample code that finds files that match the specified glob pattern.
 * For more information on what constitutes a glob pattern, see
 * http://docs.oracle.com/javase/tutorial/essential/io/fileOps.html#glob
 *
 * The file or directories that match the pattern are printed to
 * standard out.  The number of matches is also printed.
 *
 * When executing this application, you must put the glob pattern
 * in quotes, so the shell will not expand any wild cards:
 *              java Find . -name "*.java"
 */

import java.io.*;
import java.nio.file.*;
import java.nio.file.attribute.*;
import static java.nio.file.FileVisitResult.*;
import static java.nio.file.FileVisitOption.*;
import java.util.*;


public class Find {

    public static class Finder
        extends SimpleFileVisitor<Path> {

        private final PathMatcher matcher;
        private int numMatches = 0;

        Finder(String pattern) {
            matcher = FileSystems.getDefault()
                    .getPathMatcher("glob:" + pattern);
        }

        // Compares the glob pattern against
        // the file or directory name.
        void find(Path file) {
            Path name = file.getFileName();
            if (name != null && matcher.matches(name)) {
                numMatches++;
                System.out.println(file);
            }
        }

        // Prints the total number of
        // matches to standard out.
        void done() {
            System.out.println("Matched: "
                + numMatches);
        }

        // Invoke the pattern matching
        // method on each file.
        @Override
        public FileVisitResult visitFile(Path file,
                BasicFileAttributes attrs) {
            find(file);
            return CONTINUE;
        }

        // Invoke the pattern matching
        // method on each directory.
        @Override
        public FileVisitResult preVisitDirectory(Path dir,
                BasicFileAttributes attrs) {
            find(dir);
            return CONTINUE;
        }

        @Override
        public FileVisitResult visitFileFailed(Path file,
                IOException exc) {
            System.err.println(exc);
            return CONTINUE;
        }
    }

    static void usage() {
        System.err.println("java Find <path>" +
            " -name \"<glob_pattern>\"");
        System.exit(-1);
    }

    public static void main(String[] args)
        throws IOException {

        if (args.length < 3 || !args[1].equals("-name"))
            usage();

        Path startingDir = Paths.get(args[0]);
        String pattern = args[2];

        Finder finder = new Finder(pattern);
        Files.walkFileTree(startingDir, finder);
        finder.done();
    }
}

然后我用以下命令执行它：

% java Find "C:\Test" -name "*.*"

它给我输出

匹配：0

然后我写了一个简单的代码如下：

PathMatcher matcher = FileSystems.getDefault().getPathMatcher("glob:*.*");
File pollDirectoryFile = new File("C:\\Test");
File[] files = pollDirectoryFile.listFiles();
Arrays.sort(files);
for (File file : files) {
        Path path = FileSystems.getDefault().getPath(file.getName());
        if (matcher.matches(path)) {
            System.out.println(path);
        }
}

有趣的是，当它运行时，它会给我预期的输出

的abc.txt

abc.xls

有人可以指导有什么区别吗？我在Windows7上使用JDK7u25。

编辑：当我从命令行实际运行它时，它给了我正确的输出。但是，当我从我的eclipse项目中运行它时，它不起作用。

Answer 1

在我看来，您遇到的程序并未正确检查命令行。它期待arg [1]的'-name'，但是用法表明它实际上是arg [2]。使用调试器自行检查。

这是一个简单的修复，我将留给你解决。

Java glob查找文件

1 个答案: